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3 years ago

Find the volume of the sphere. Round to the nearest tenth, if necessary. (Use π = 3.14)

Mathematics

1 answer:

ankoles [38]3 years ago

6 0

Steps:

Shape: Sphere

Solved for volume

Radius: 3

Formula: V=4 /3πr3

1: know the height. We don't have to round to the nearest tenth. The correct answer for this question is 113.0.

Answer: 113.0

Please mark brainliest

Hope this helps.

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I'm trying to find out the number of how much it cost to wrap each present, day one 41 small gifts were wrapped and 45 large wer

Licemer1 [7]

Answer:

Small gift: $2

Large gift: $7

Step-by-step explanation:

Let x represent cost of wrapping each small gift and y represent cost of wrapping each large gift.

We have been given that day one 41 small gifts were wrapped and 45 large were wrapped equaling $397.

We can represent this information in an equation as:

$41x+45y=397...(1)$

We are also told that day two 30 small gifts were wrapped and 47 large were wrapped equaling $389. We can represent this information in an equation as:

$30x+47y=389...(2)$

From equation (1), we will get:

$x=\frac{397-45y}{41}$

Upon substituting this value in equation (2), we will get:

$30(\frac{397-45y}{41})+47y=389$

$\frac{11910-1350y}{41}+\frac{47*41y}{41}=389$

$\frac{11910-1350y+1927y}{41}=389$

$\frac{11910+577y}{41}=389$

$\frac{11910+577y}{41}\cdot 41=389\cdot 41$

$11910+577y=15949$

$11910-11910+577y=15949-11910$

$577y=4039$

$\frac{577y}{577}=\frac{4039}{577}$

$y=7$

Therefore, cost to wrap a large gift is $7.

Upon substituting $y=7$ in equation $x=\frac{397-45y}{41}$ , we will get:

$x=\frac{397-45(7)}{41}$

$x=\frac{397-315}{41}$

$x=\frac{82}{41}$

$x=2$

Therefore, cost to wrap a small gift is $2.

8 0

3 years ago

Write each whole number in expanded form.

Phantasy [73]

A) 200,000 + 40,000 + 4,000 + 300 + 6

b) 70,000,000 + 7,000,000 + 70,000+ 9,000 + 100 + 1

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3 years ago

Find the valur.of BAC

Lady_Fox [76]

Answer:

X=30

The whole triangle = 180 degrees

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3 years ago

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A 6 ft tall tent standing next to a cardboard box casts a 15 ft shadow. if the cardboard box casts a shadow that is 6 ft long th

ohaa [14]

What we know is that a 6 foot tall tent casts a 15 foot shadow. Lets represent that given this way: 6 = 15
So, the unknown (y), or what we want to know, is how tall the cardboard box if it has a 6 foot long shadow (noticeably the same height as the tent):
y = 6

6 = 15
y = 6

(6 x 6) / 15 = y
36 / 15 = y
2.4 = y

The height of the cardboard box is 2.4 feet.

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3 years ago

0.1 x 23 Please help me

zhannawk [14.2K]

Answer:

the answer would be 2.3

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3 years ago

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