Solve the equation. 2(3z-2)+8=34 A. z=3 B. z=-3 C. z=-4 D. z=5
2 answers:
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Given:
The given quadratic polynomial is :
To find:
The quadratic polynomial whose zeroes are negatives of the zeroes of the given polynomial.
Solution:
We have,
Equate the polynomial with 0 to find the zeroes.
Splitting the middle term, we get
The zeroes of the given polynomial are -3 and 4.
The zeroes of a quadratic polynomial are negatives of the zeroes of the given polynomial. So, the zeroes of the required polynomial are 3 and -4.
A quadratic polynomial is defined as:
Therefore, the required polynomial is .