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2 years ago

2x+3y=12

Mathematics

1 answer:

Radda [10]2 years ago

7 0

The answer would be (6,8)

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Identifying the equivalent expression

iragen [17]

Answer:

$\large\boxed{\sqrt{x+3}=(x+3)^\frac{1}{2}}$

Step-by-step explanation:

$\text{Use}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\\sqrt{x+3}=\sqrt[2]{x+3}=(x+3)^\frac{1}{2}$

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3 years ago

What is the equation of the line that passes through the point (3,4) and has a slope of zero

Lemur [1.5K]

Answer:

y = 4

Step-by-step explanation:

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3 years ago

HELP PLEASE ,, i need the right answer

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Answer:

It's the first one

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3 years ago

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Describe the Glide Reflection from the preimage triangle in Black to the image triangle and red

cestrela7 [59]

We want the final coordinate of K to become (-3,1). If you reflect across the y-axis, you transform

$(x,y)\mapsto(-x,y)$

So, we need to move K to (3,1), and then reflect it across the y-axis. Since K starts at (-1,4), we have to move it 4 units to the right and 3 units down.

4 0

2 years ago

15. Construct the slope-intercept form equation of the line passing through (-5,23) and (10,-5).

Radda [10]

Answer:

15y = -28 x + 205.

Step-by-step explanation:

Slope intercept form of equation is y = mx + c where m is slope and c is the y intercept.

Now slope of line passing through points (-5, 23) and (10, -5):

$m = \frac{y_{2} - y_{1} }{x_{2} - x_{1} } = \frac{-5 -23}{10 + 5} = \frac{-28}{15}$

Now equation of line:

y = mx + c

substituting the value of m in above expression,

$y = -\frac{28}{15} x + c$

Now, since the line is passing through the point (-5, 23) therefore, x = -5 and y = 23. By substituting these values in above equation,

$23 = -\frac{28}{15} \times (-5) + c$

$23 = \frac{28}{3} + c$

$c = 23 - \frac{28}{3} = \frac{69 - 28}{3} = \frac{41}{3}$

So equation of line in slope intercept form:

$y = -\frac{28}{15} x + \frac{41}{3}$

Further solving,

15y = -28 x + 205.

3 0

3 years ago