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WITCHER [35]
3 years ago
15

During which part of an examination are various body parts and organs touched and felt?

Computers and Technology
1 answer:
scoray [572]3 years ago
8 0

The correct answer is B. Palpation

Explanation:

In a medical exam or similar, the palpation involves touching different parts of the body to feel the organs and structures in this. This process is essential in diagnosis because palpation can reveal inflammation, pain in certain areas, or abnormalities. Additionally, palpation requires a broad knowledge of anatomy that allows health professionals to understand the structures of the body when they touch these and how to determine abnormalities. Thus, the part of an examination in which body parts are touched and felt is palpation.

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olya-2409 [2.1K]

Answer:

it goes to the deleted items area

Explanation:

but it also depends on where you deleted it on

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Is this photo considered rim photography
xenn [34]

Answer:

No

Explanation:

The photo in the question is just a black and white filter whereas in Rim photo, the image subject is backlit and the image is exposed to hide the subject features in shadow.

An example of Rim photography.

7 0
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A measure of the twisting or rotational force that an engine can produce is called
Snowcat [4.5K]
The correct answer is torque.

Torque
A twisting force that tends to cause rotation, commonly used term among mechanics and engineers.
7 0
3 years ago
Write a program that reads a list of words. Then, the program outputs those words and their frequencies. The input begins with a
tekilochka [14]

Answer:

The following are the program to the given question:

import java.util.*;//import package for user input

public class Make  //define class Make

{

public static void main(String[] ask)  //define a main method

{

  Scanner obx = new Scanner(System.in);   //declare the Scanner class object

  int size=obx.nextInt(); //get the size of the array from the user

  int a[]=new int[size]; //declare an integer array with given size

  String word[]=new String[size]; //declare a string array with given size

  for(int i=0;i<size;i++) //set the for loop  

  word[i]=obx.next(); //get string input from the user

  for(int i=0;i<size;i++)   //iterates with the array, increase the count

  {

    for(int j=0;j<size;j++)   //defining a loop to check value

    {

      if(word[i].equals(word[j]))  //use if to check that elements of words          

      a[i]++;//increamenting array size

    }

  }

 System.out.print("\n");  //use print for break line  

  for(int i=0;i<size;i++)//set for loop to print the following result

    System.out.println(word[i]+" "+a[i]);//print value

 }

}

Output:

Please find the attachment file.

Explanation:

  • First, establish the predefined package required and instead define the main class and define the main method within the class and method.
  • Declare the scanner class object and receive an object size in the 'size' variable thru the array.
  • Next create two arrays, the integer type "a" with both the input size given and the string type "word" with the input size supplied.
  • Define the loop for which string array elements are acquired and set two to again for loop, which increases with loop iteration the integer data type array by one.
  • Lastly, set the loop for which this result is printed.

5 0
3 years ago
Print "Censored" if userInput contains the word "darn", else print userInput. End with newline. Ex: If userInput is "That darn c
barxatty [35]

Answer:

#include <string>

#include <iostream>

using namespace std;

int main() {

string userInput;

getline(cin, userInput);

// Here, an integer variable is declared to find that the user entered string consist of word darn or not

int isPresent = userInput.find("darn");

if (isPresent > 0){

cout << "Censored" << endl;

// Solution starts here

else

{

cout << userInput << endl;

}

// End of solution

return 0;

}

// End of Program

The proposed solution added an else statement to the code

This will enable the program to print the userInput if userInput doesn't contain the word darn

6 0
3 years ago
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