Hey there!!
Let's take the number as x and y
Given,
The sum of x and y = 12
One number is 2 more than the other
Let's take y = x + 2
Equations
x + y = 12
As we know y = x + 2 , plug the value in
x + x + 2 = 12
2x + 2 = 12
Subtract 2 on both sides
2x = 10
Divide by 5 on both sides
x = 5
y = 2 + x
y = 7
The numbers are 5 and 7
Hope my answer helps!
Answer:
Option B has infinitely many solutions.
21:18, 42:36, 73:54.
Basically numbers that can be multiplied from the original ratios. Like 7:3, 21:18. 7 is mulitplied 3 times to get 21 and 18 is mulitiplied by 3 7 times to get it. Hope that helps.
<span>There are 100 possible pairs of numbers.
Half of them start with an even number so only 50 have a first odd number.
Of those remaining 50, half of those have an odd second number.
Leaving 25 of the original 100 to have two odd numbers.
P= 25/100=1/4</span>
Answer:
she received 21 more
Step-by-step explanation:
43 + 34 =77
98-77= 21
Hope this helps!!!
