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2 years ago

11

I don’t know what to do, can someone people help me? Thank you

1 answer:

Dennis_Churaev [7]2 years ago

7 0

The problem asks which two triangles are congruent, or identical.

The correct answer is B) ΔDEF ≅ ΔJKL

Angle D corresponds to angle J, at 38°
Angle E corresponds to angle K, at 46°
Angle F corresponds to angle L, at 96°
Angles are congruent.

Side DE corresponds to side JK, at 8.8cm.
Side FE corresponds to side LK, at 5.4cm.
Sides are congruent.

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Which statement is not true? a.All nunbers are natural numbers.b.Fractions are rational numbers.c.Zero is an integer.

DiKsa [7]

I believe that b.Fractions are rational numbers is not true

sorry if its wrong

6 0

2 years ago

Read 2 more answers

I need to increase my sales by 35% in order to meet my goal for the month you currently have 45 sales and you will need to get b

cluponka [151]

Answer:

61 sales

Step-by-step explanation:

First find the increase

45 * 35%

45*.35

15.75

Add this to your sales

45+15.75

60.75

Since you cannot have part of a sale, round up

61 sales

6 0

2 years ago

Consider the function f(x)=−3/4 x+1.

jenyasd209 [6]

-(3/4) (12)+1 = -9+1=. -8

7 0

2 years ago

Please help me before it's to late I

gregori [183]

It’s 7.406 , that’s the correct answer

5 0

2 years ago

PLEASE HELP AND ANSWER!!!!! Which of the following reveals the minimum value for the equation 2x2 + 12x − 14 = 0?

NARA [144]

Answer:

The correct option is 3.

Step-by-step explanation:

The given equation is

$2x^2+12x-14=0$

It can be written as

$(2x^2+12x)-14=0$

Taking out the common factor form the parenthesis.

$2(x^2+6x)-14=0$

If an expression is defined as $x^2+bx$ then we add $(\frac{b}{2})^2$ to make it perfect square.

In the above equation b=6.

Add and subtract 3^2 in the parenthesis.

$2(x^2+6x+3^2-3^2)-14=0$

$2(x^2+6x+3^2)-2(3^2)-14=0$

$2(x+3)^2-18-14=0$

$2(x+3)^2-32=0$ .... (1)

Add 32 on both sides.

$2(x+3)^2=32$

The vertex from of a parabola is

$p(x)=a(x-h)^2+k$ .... (2)

If a>0, then k is minimum value at x=h.

From (1) and (2) in is clear that a=2, h=-3 and k=-32. It means the minimum value is -32 at x=-3.

The equation $2(x+3)^2=32$ reveals the minimum value for the given equation.

Therefore the correct option is 3.

5 0

2 years ago