The value of
exists 1061208.
<h3>How to estimate the value of

?</h3>
Let us rewrite
as 
Now utilizing the identity
, we get
a = 100 and b = 2 then substitute the values of a and b then
![(100+2)^3=100^3+2^3+[(3\times100\times2)(100+2)]](https://tex.z-dn.net/?f=%28100%2B2%29%5E3%3D100%5E3%2B2%5E3%2B%5B%283%5Ctimes100%5Ctimes2%29%28100%2B2%29%5D)
= 1000000 + 8 + (600 × 102)
= 1000000 + 8 + 61200
= 1061208
Hence, 
Therefore, the value of
exists 1061208.
To learn more about cubic polynomial equation refer to:
brainly.com/question/28181089
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A possible perimeter for the rectangle would be 28
Area=L x W
40/10=4
Width=4, Length=10
Perimeter=L+L+W+W
4+4+10+10=28
Answer: b=6
Step-by-step explanation:
6 is in the y intercept place so it equals 6
Answer:
The pebble will hit the ground 8.29 second after it is thrown.
Step-by-step explanation:
Given that,
The height of the pebble after t seconds is given by the equation
h= -16t²+24 t+900.
When the pebble hit the ground, the height of the pebble will be zero.
So putting h=0 in the given equation.
0 = -16t²+24 t+900
⇒-4(4t²-6t-225)=0
⇒4t²-6t-225=0
Applying quadratic formula
, here a=4, b= -6 and c= -225.

⇒ t = 8.29, -6.79
Since time can not negative.
∴t=8.29 seconds.
The pebble will hit the ground 8.29 second after it is thrown.