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Minchanka [31]
3 years ago
6

FInd the distance between the points (9,3) and (1,9)

Mathematics
1 answer:
BARSIC [14]3 years ago
3 0

Answer:

=10

Step-by-step explanation:

1: Add the numbers

2: Factor the numbers

3: Apply radical rule

Answer: =10

<u><em>Hope this helps.</em></u>

You might be interested in
Solve the Inequality<br> 9w-4w+6≥1+5w
vivado [14]

Answer: All real numbers :)

7 0
3 years ago
Simplify the expressions. Show your work.
Hunter-Best [27]
7) Use distributive property
3x(4x⁴ - 5x)=3x*4x⁴- 3x*5x = 12x⁵ - 15x²
8) When you open parenthesis with minus sigh in front of it, you need change sings of the terms on opposite. Then find like terms.
(5x⁴-3x³+6x)-(3x³+11x²-8x)= 5x⁴-3x³+6x -3x³-11x²+8x =5x⁴-6x³ - 11x²+14x
9)(x-2)(3x-4)=x*3x-4x-6x+8=3x²-10x+8
10) (x+6)²=(x+6)(x+6)=x²+6x+6x+36=x²+12x+36
For (x+6)², you can also use the formula of the perfect square
(a+b)²=a²+2ab+b²
For (x+6)² =x²+2*x*6 +6²=x²+12x+36


5 0
3 years ago
Here are four digits.
Bogdan [553]

Answer:

A: 357

(1) 9641

Step-by-step explanation:

With A you really just want to go from the smallest number up so it would be the smallest number possible.

<em>EX.</em> 357 vs. 736   357 is smaller

With 1 you have to go from the highest number to lowest number to get the biggest answer possible.

<em>Ex.</em>  9641 vs. 1946    9641 is larger.

3 0
3 years ago
THIS IS URGENT I AM BEING TIMED IF YOU ANSWER I WILL MARK YOU BRAINLYIST.
lapo4ka [179]

Answer:

It's 0.3. Hope this helps!

Step-by-step explanation:

3 0
3 years ago
The perimeter of a triangle is 199 inches. If one side of the triangle is six more than the shorter side, and the longer side is
Keith_Richards [23]
Shortest side (a) = 58
middle side (b) = 64
longest side (c) = 77

the 3 sides a + b + c = 199
b = a + 6
c = a + 19

substitute your new values for b & c into your original formula, so:
a + (a+6) + (a+19) = 199
3a + 25 = 199
3a = 174
a = 58

then substitute 58 into your b & c formulas to figure out the rest
b = a + 6 = 58 + 6 = 64
c = a + 19 = 58 + 19 = 77

3 0
3 years ago
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