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2 years ago

What is the parametric form of the line r=(2,-3,0) + t (1,0,-1)?

Mathematics

1 answer:

NeX [460]2 years ago

6 0

Answer:

Step-by-step explanation:

r=(2,-3,0) + t (1,0,-1)

r=(2+t, -3+0t,0+(-t))

x(t)=2+t

x(t)=t+2

y(t)=0t-3

y(t)=-3

z(t)=0+(-t)=-t

z(t)=0-t

z(t)=-t

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Write a rule to describe a translation 5 units left and 10 units up.

madam [21]

To translate 5 units left, add 5 to every x to move up 10 units, add 10 to whole equaiotn example y=2x+2 move left 5 y=2(x+5)+2 move up 10 y=2(x+5)+2+10

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2 years ago

(x-2)times (x^2+8x-1)

DerKrebs [107]

Answer:

x^3+6x^2-17x+2

Step-by-step explanation:

(x-2)*(x^2+8x-1)

=x(x^2+8x-1)-2(x^2+8x-1)

=x^3+8x^2-x-2x^2-16x+2

collect like terms

= x^3+6x^2-17x+2

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3 years ago

What is the equation, in standard form, of a parabola that models the values in the table?

love history [14]

Answer:

$Y=4x^2+3x-6$

Step-by-step explanation:

For the standard form equation to model the values in the table, each value of x in the table should give the matching the y value when substituted into the equation. We will test each equation:

$Y=3x^2+4x-6$ for (-2,4)

$Y=3(-2)^2+4(-2)-6=3(4)+-8-6=12+-8-6=-2\\$

This does not give 4 as the answer and is not a solution.

$Y=4x^2+3x-6$ for (-2,4)

$Y=4(-2)^2+3(-2)-6=4(4)+-6-6=16+-6-6=-4\\$

This does give 4 as the answer and is a possible solution.

$Y=4x^2-3x-6$ for (-2,4)

$Y=4(-2)^2-3(-2)-6=4(4)+6-6=16+6-6=16\\$

This does not give 4 as the answer and is not a solution.

$Y=-4x^2-3x-6$ for (-2,4)

$Y=-4(-2)^2-3(-2)-6=-4(4)+6-6=-16+6-6=-16\\$

This does not give 4 as the answer and is not a solution.

The only possible solution is $Y=4x^2+3x-6$

3 0

3 years ago

Find the midpoint of the segment with the given endpoints. 4 and 11

brilliants [131]

Hey there!!

How do we find the midpoint?

We take the average , the average is =

Sum of the observations / total number of observations

The end points are given as 4 and 11

Sum = 11 + 4

Number of observations = 2

= 15 / 2

= 7.5 is the midpoint

4 0

3 years ago

Read 2 more answers

She is serving hot coffee and cold coffee in two rectangular-shaped tanks, each with dimensions width 8.75 inches, length 8.75 i

Blababa [14]

The volume of the coffee in each tank will be 1760. in³. The mass of cold coffee and hot coffee will be 6163.29 oz and 10213.45 oz. Then the number of the tank placed on a table is one only.

<h3>How to find the density and volume?</h3>

She is serving hot coffee and cold coffee in two rectangular-shaped tanks, each with dimensions width of 8.75 inches, a length of 8.75 inches, and a height of 23 inches.

The hot coffee has a density of 5.8 oz/in³ and the cold coffee has a density of 3.5 oz/ in³.

Then the volume of the coffee in each tank will be

We know that the dimension of both tanks is equal. Then the volume will remains equal.

Volume = L × B × H

Volume = 8.75 × 8.75 × 23

Volume = 1760.9375 ≅ 1760.94 in³

Then the mass of the coffee in each the tank will be

The mass of hot coffee will be

Mass = Density × Volume

Mass = 5.8 × 1760.94

Mass = 10213.45 oz

The mass of cold coffee will be

Mass = Density × Volume

Mass = 3.5 × 1760.94

Mass = 6163.29 oz

Then the number of the tank placed on a table is one only.

More about the density and volume link is given below.

brainly.com/question/952755

#SPJ1

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2 years ago