Pls help me to solve this

Mathematics

1 answer:

zloy xaker [14]3 years ago

4 0

Answer:

see below

Step-by-step explanation:

19-3 will be greater

We are multiplying 1/2 *(19-3) which is multiplying by a number less than 1 it will be less than 1

18-3 = 16

1/2 * (19-3)

Using PEMDAS

We do parentheses first

1/2 ( 16)

Then multiply

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Flura [38]

A geometric sequence is a sequence of numbers that follows a pattern where the next term is found by multiplying by a constant called the common ratio, q:

$a_n=a_{n-1}\cdot q=(a_{n-2}\cdot q)\cdot q=a_{n-2}\cdot q^2=...,\\ a_n=a_1\cdot q^{n-1}$ .

Given the functions $f(n)=11$ and $g(n)=\left(\dfrac{3}{4}\right)^{n-1}$ , you can consider $a_n=11\cdot \left(\dfrac{3}{4}\right)^{n-1}$ as n-th term of the geometric sequence with first term $a_1=11$ and common ratio $q=\dfrac{3}{4}$ .