Yo has to factor since we assume that
if you have xy=0, x and y=0
7n^2-48n+36=0
trial and error
(7n-6)(n-6)=0
set each to zero
7n-6=0
add 6
7n=6
divide 7
n=6/7
n-6=0
add 6
n=6
n=6/7 or 6
The first way to try to fix this is to apply logarithm to the observations on the dependent variable. This is going to make the dependent variable with high degree of kurtosis normal.
Note that sometimes, the resulting values of the variable will be negative. Do not worry about this, as it is not a problem. It does not affect the regression coefficients, it only affects the regression intercept, which after transformation, will be of no interest.
First let you know what to do. OK. Going to drag a ruler. Across the paper. Vertically. And if it touches 2 points on the grid. Then it fails the test.
Answer:
i dont know the answer sorry
Step-by-step explanation:
The formula of a midpoint:
We have:
Substitute
<h3>Answer: (-2, -4)</h3>
