Which undefined term is used to define an angle? O line O plane Opoint O ray

Suppose twenty-two communities have an average of = 123.6 reported cases of larceny per year. assume that σ is known to be 36.8

Delvig [45]

We are given the following data:

Average = m = 123.6
Population standard deviation = σ= psd = 36.8
Sample Size = n = 22

We are to find the confidence intervals for 90%, 95% and 98% confidence level.

Since the population standard deviation is known, and sample size is not too small, we can use standard normal distribution to find the confidence intervals.

Part 1) 90% Confidence Interval
z value for 90% confidence interval = 1.645

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.645* \frac{36.8}{ \sqrt{22}}=110.69$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.645* \frac{36.8}{ \sqrt{22}}=136.51$

Thus the 90% confidence interval will be (110.69, 136.51)

Part 2) 95% Confidence Interval
z value for 95% confidence interval = 1.96

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.96* \frac{36.8}{ \sqrt{22}}=108.22$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.96* \frac{36.8}{ \sqrt{22}}=138.98$

Thus the 95% confidence interval will be (108.22, 138.98)

Part 3) 98% Confidence Interval
z value for 98% confidence interval = 2.327

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-2.327* \frac{36.8}{ \sqrt{22}}=105.34$
Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+2.327* \frac{36.8}{ \sqrt{22}}=141.86$

Thus the 98% confidence interval will be (105.34, 141.86)

Part 4) Comparison of Confidence Intervals
The 90% confidence interval is: (110.69, 136.51)
The 95% confidence interval is: (108.22, 138.98)
The 98% confidence interval is: (105.34, 141.86)

As the level of confidence is increasing, the width of confidence interval is also increasing. So we can conclude that increasing the confidence level increases the width of confidence intervals.

3 0

3 years ago

I NEED IT RIGHT NOW ILL GIVE 40 POINTS .....During a black friday sale, Sophia picks up the last big screen tv. The mom behind h

Doss [256]

Answer:

The mom would offer her 150% of 350

=> 150/100 * 350

=> 3/2 * 350

=> 1050/2

=> 525

Therefore, the mom would offer her 525 dollars

If my answer helped, please mark me as the brainliest!!!

Thank You!!

7 0

2 years ago

Read 2 more answers

Bro help me out for a brainly and show work

Natasha_Volkova [10]

Answer:

Definitely Function B

Step-by-step explanation:

Because when you solve the equation it intercepts the X axis

3 0

2 years ago

Read 2 more answers

What is the sum of 2.5 x 10^4 and 3.4 x 10^4

navik [9.2K]

5.9 x 10^4

59000

That is the answer C

3 0

3 years ago

Use the distributive property to solve the equation 28-(3x+4)=2(x+6)+x. Show your work.

Gre4nikov [31]

Answer:

x=2

Step-by-step explanation:

28−(3x+4)=2(x+6)+x

We need to use the distributive property for the right side.

28−3x−4=(2)(x)+(2)(6)+x)

28−3x−4=2x+2+x

−3x+24=3x+12

From here we need to subtract 3x from both side.

−3x+24−3x=3x+12−3x

6x+24=12

Transfer +24 on the right side.

6x=12−24

6x=−12

Finally, divide both sides by −6

6x/-6 = -12/-6

x=2

6 0

2 years ago