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Ray Of Light [21]
3 years ago
5

Name an additional pair of parts that are congruent needed to prove △abc≅△dbc if cb¯¯¯¯¯⊥ad¯¯¯¯¯ and bc¯¯¯¯¯≅bc¯¯¯¯¯.

Mathematics
1 answer:
Anastaziya [24]3 years ago
6 0
You seem smart do you want help me
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A home has a room with length 22 feet and width 25 ft.
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O length = 11 inches width = 12.5 inches

Step-by-step explanation:

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A zookeeper measured the length of 5 snakes at the zoo he recorded the results in a table. what is the main snake length?
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I'm 90% sure the answer is twenty-six cm.
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HELP ME I NEED HELP LIKE RIGHT NOW OH GOSH
nataly862011 [7]

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is this in a test

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2 years ago
A golfer keeps track of his score for playing nine holes of golf​ (half a normal golf​ round). His mean score is 8080 with a sta
solniwko [45]

Answer:

Therefore the mean and standard deviation of his total score if he plays a full 18 holes are 160 and 11\sqrt2 respectively.

Step-by-step explanation:

Given that,

For the first 9 holes X:

E(X) = 80

SD(X)=13

For the second 9 holes Y:

E(Y) = 80

SD(Y)=13

For the sum W=X+Y, the following properties holds for means , variance and standard deviation :

E(W)=E(X)+E(Y)

     and

V(W)=V(X)+V(Y)

⇒SD²(W)=SD²(X)+SD²(Y)        [ Variance = (standard deviation)²]

\Rightarrow SD(W)=\sqrt{SD^2(X)+SD^2(Y)}

∴E(W)=E(X)+E(Y) = 80 +80=160

            and

∴SD(W)=\sqrt{SD^2(X)+SD^2(Y)}

              =\sqrt{11^2+11^2}

               =\sqrt{2.11^2}

               =11\sqrt2

Therefore the mean and standard deviation of his total score if he plays a full 18 holes are 160 and 11\sqrt2 respectively.

                                               

4 0
3 years ago
Please I need help with this and show your steps
Lorico [155]

Answer:

-30/15 or -2

Step-by-step explanation:

2+8 = 10

3+2 = 5

14-2 = 12

4-1 = 3

10/5 - 12/3

(Find GCF)(GCF = 15)(5 times 3)

30/15 (10/5 times 3)

60/15 (12/3 times 5)

30/15 - 60/15 = -30/15 --> -2(simplified to 2)

7 0
2 years ago
Read 2 more answers
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