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Ray Of Light [21]
3 years ago
5

Name an additional pair of parts that are congruent needed to prove △abc≅△dbc if cb¯¯¯¯¯⊥ad¯¯¯¯¯ and bc¯¯¯¯¯≅bc¯¯¯¯¯.

Mathematics
1 answer:
Anastaziya [24]3 years ago
6 0
You seem smart do you want help me
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What is an equation of the line that is parallel to y=3x-8 and passes through (1,8)
Alla [95]

Answer:

y = 3x + 5

Step-by-step explanation:

Two lines which are parallel have the same gradient. This means that the parallel line must have a gradient of 3x

y = 3x + c

To figure out c you substitute in the given coordinate for the x and y values

8 = 3(1) + c

c = 5

y = 3x + 5

4 0
3 years ago
What is cosine ? I really need this answer for my test tomorrow. Please help
Kisachek [45]
Cosine is \frac{adjacent}{hypotenuse} which applies to a right triangle. I hope that helps you.
3 0
3 years ago
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4-4x-9x how many terms
11Alexandr11 [23.1K]

Answer:

3 terms

Step-by-step explanation:

4 4x and 9x

5 0
2 years ago
A regular hexagon has sides of 3 feet. What is the area of the hexagon?
frosja888 [35]

Answer:

13.5\sqrt{3}\:\text{ft}^{2}

Step-by-step explanation:

Given: The side of a regular hexagon is 3 feet.

To find: Area of the hexagon

Solution:

It is given that the side of a regular hexagon is 3 feet.

We know that the area of a regular hexagon whose side is a units is \frac{3\sqrt{3} }{2} a^{2}

Here, the side is 3 feet

So, area of the regular hexagon

=\frac{3\sqrt{3} }{2} \times3^{2}

=\frac{3\sqrt{3} }{2} \times9

=\frac{27\sqrt{3} }{2}

=13.5\sqrt{3}\:\text{ft}^{2}

Hence, area of the regular hexagon is 13.5\sqrt{3}\:\text{ft}^{2}

6 0
3 years ago
Need to be able to check this assignment for my son and I have no clue how to make sure it's correct anyone?
saw5 [17]

Answer:

it is correct

Step-by-step explanation:

4 0
3 years ago
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