Converse (switch p and q)
If an angle is obtuse, then it measures 128°
This is false (a 127° angle is obtuse, but it does not measure 128°)
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Inverse (negations of p and q)
If an angle does not measure 128°, then it is not obtuse
This is false (a 127° angle does not measure 128°, but it is obtuse)
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Contrapositive (negations of p and q, then switch their places)
If an angle is not obtuse, it does not measure 128°
This is true (any 128° is obtuse; no exceptions)
Answer:some where from 65-75 feet
Step-by-step explanation:
Answer:
Step-by-step explanation:
Length = L.
Width = 2L-3.
A = L * W = 170.
L * (2L-3) = 170.
2L^2 - 3L - 170 = 0,
L = (-B +- Sqrt(B^2-4AC))/2A.
L = (3 +- Sqrt(9 + 1360))/4,
L = (3 +- 37)/4 = 0.75 +- 9.25 = 10, and -8.5. In.
Use positive value: L = 10 In.
The two expressions that are comparable to one another for the total cost of the cloth are and
(7.99 × 7/3) and 18.64
This is further explained below.
<h3>What is
expressions ?</h3>
In most cases, the two expressions that are comparable to one another for the total cost of the cloth are
(7.99 × 7/3) and 18.64
Total cost = Cost of fabric per yard * Number of fabrics
= 7.99 × 2 1/3
= (7.99 × 7/3)
= 55.93 / 3
= 18.64
As a result, the two expressions that are comparable to one another for the total cost of the cloth are and
(7.99 × 7/3) and 18.64
Learn more about total cost:
brainly.com/question/2021001
#SPJ1
Answer:
- b/a
- 16a²b²
- n¹⁰/(16m⁶)
- y⁸/x¹⁰
- m⁷n³n/m
Step-by-step explanation:
These problems make use of three rules of exponents:
In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)
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1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.
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2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.
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3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.
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4. This works the same way the previous problem does.
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5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.
