Answer:
Here is the full question:
(A) If a closed container contains a mouse as well as enough food, water, and oxygen for the mouse to live for 3 weeks,
How much will the container weigh 1 and 2 weeks later after the mouse has eaten, drunk and exercised (respiration is CO2 emission), and why?
(B) If the mouse was in a wire cage and only the weights of the mouse, food, and water were considered, would you come to the same answer as in (A) and why?
Explanation:
(A) The mouse will weigh the same. This is because solids, liquid, and gases cannot escape the closed container. All of the life processes involving reactions conserve the atoms involved. Some of those atoms will appear in the form of gases, some as solids, and others as liquids but all will be retained in the closed container.
(B) In a wire cage, gases can escape. This means that the weight will not be the same after 1 and 2 weeks. The weight would be less than the original weight of the mouse, it's food, and it's water.
Answer:Multicellular and Eukaryotic are traits that can be true for every Kingdom past Protists on this branching tree diagram. These are the traits which were evolved that Protists just missed, plants and fungi got these traits and transferred them to their descent as well.
Explanation:
Plant cells are specialized for life in a hypotonic environment.
Answer: Option A
<u>Explanation:</u>
A cell which lacks the cell wall, will expand and burst. At the point when set in a hypertonic solution, a cell without a cell wall will lose water to the surrounding, wilt and presumably die.
In a hypertonic arrangement, a cell with a cell divider will lose water as well. The plasma layer pulls from the cell wall as it withers, a procedure called plasmolysis. Thus it can be inferred that plant cell are specialized for life in a hypotonic environment.
Golgi apparatus is your awser to the question
