Hi
mn^0
= m
Answer: B
I hope that's help !
Good night !
Answer:
c. dP/dt = (1/5)P
Step-by-step explanation:
Given that the rate of change of population with respect to time dP/dt is directly proportional to the population, P, we have
dP/dt ∝ P
dP/dt = kP
Given that dP/dt = 2 million insects per day and P = 10 million insects after 5 days, So,
2 = k × 10
k = 2/10
k = 1/5
So, dP/dt = kP
dP/dt = (1/5)P
101
8x - 4y + 12
-2(-4x + 2y - 6)
(-2)(-4x) + (-2)(2y) + (-2)(-6)
(2 * 4x) - (2 * 2y) + (2 * 6)
log(xy)
Do notice that this only works when the bases of the logs are the same
written in exponent form, this rule is : a^x * a^y = a^(x+y)