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dezoksy [38]
2 years ago
5

What is the constant rate of change in the equation? Y=3x+9

Mathematics
1 answer:
katovenus [111]2 years ago
3 0

Answer:

3

Step-by-step explanation:

3 is the slope and so it is the rate of change

Sorry brainly deleted my previous answer

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The cost of fencing a square garden at the rate of Rs.5 per
Alex787 [66]

\huge\underline{\overline{\mid{\bold{\red{ANSWER}}\mid}}}

Cost per metre = Rs. 5

Total cost = Rs. 2000

Then total length of the fence = Rs.2000/Rs.5

= 400 metre

Total length of the fence = 400 metre

4 0
3 years ago
Charlie invests £1200 at 3.5% per annum compound interest.
lbvjy [14]

Answer:

<h2>£1,330.46</h2>

Step-by-step explanation:

Using the compound interest formula A = P(1+\frac{r}{n} )^{nt}

A = amount compounded after n years

P = principal (amount invested)

r = rate (in %)

t = time (in years)

n = time used to compound the money

Given P =  £1200., r = 3.5%, t = 3years, n = 1 year(compounded annually)

A = 1200(1+0.035)^{3}\\ A = 1200(1.035)^{3}\\ A = 1200* 1.108717875\\A = 1,330.46

Value of Charlie's investment after 3 years is £1,330.46

6 0
3 years ago
Answer please You feeling lucky punk
Ksivusya [100]

Answer:

Final velocity is 3

Change in velocity is 4

Initial velocity is 2

Instantaneous velocity is 1

Acceleration is 5

7 0
2 years ago
How do I solve for x?
notka56 [123]
Solving:
\frac{3+4x}{2} + \frac{5-x}{3} = \frac{29}{6}
Make the Least Common Multiple (2,3,6)
2,3,6\:|2
1,3,3\:|3
1,1,1\:|\underline{2*3=6}


<span>Replace denominators and resolve:
</span>\frac{3+4x}{2} + \frac{5-x}{3} = \frac{29}{6}
\frac{3(3+4x)}{6} + \frac{2(5-x)}{6} = \frac{29}{6}
Cancel the dominators
\frac{3(3+4x)}{\diagup\!\!\!\!6} + \frac{2(5-x)}{\diagup\!\!\!\!6} = \frac{29}{\diagup\!\!\!\!6}
3(3+4x) + 2(5-x) = 29
9 + 12x + 10 - 2x = 29
12x - 2x = 29 - 9 - 10
10x = 20 - 10
10x = 10
x =  \frac{10}{10}
\boxed{\boxed{x = 1}}\end{array}}\qquad\quad\checkmark


7 0
3 years ago
CAN YOU HELP ME PLEASE
mamaluj [8]

Answer:

A

Step-by-step explanation:

7 0
3 years ago
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