A right triangle is drawn on a coordinate plane. Two vertices of the triangle are points R(−9,6) and T(10,−7) . The third vertex
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The missing words to complete the proof are respectively; Vertical Angles; Corresponding angles; Transitive Property
<h3>How to prove congruent angles?</h3>The image of the transversal line is attached.
1) We know that lines a and b are parallel and that line c is a transversal because that is given.
2) We can tell that angles 2 and 5 are congruent because vertical angles are congruent.
3) Angles 5 and 7 are congruent because corresponding angles by parallel lines cut by a transversal are congruent.
4) Therefore, angles 2 and 7 are congruent based on the transitive property.
Read more about Congruent Angles at; brainly.com/question/1675117
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Answer:
a= -6
Step-by-step explanation:
Please see attached picture for full solution.
I skipped a few steps while rewriting the equation into the form of y=mx+c
Here's the step-by-step working if you don't understand:
2x -3y= 6
2x= 3y +6 (+3y on both sides)
2x -6= 3y (-6 on both sides)
3y= 2x -6
<em>y= 2/3x -2</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>(÷3 throughout)
