What is the highest common factor of 42 and 90
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We can find m∠BCD like follows: m∠BCD=90°-45°=45<span>°
Now, m</span><span>∠DBC= 180°-(90°+45°)=45°
Remember that </span>
, so 
We know that hypotenuse= BC= 3in and
=∠DBC)=45°, so replacing the values we get:
We can conclude that the segment CD is 2.12 in
Now, m</span><span>∠DBC= 180°-(90°+45°)=45°
Remember that </span>
We know that hypotenuse= BC= 3in and
We can conclude that the segment CD is 2.12 in