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expeople1 [14]
3 years ago
13

I will mark you as most Brillance if you help me get this right!

Mathematics
1 answer:
Dovator [93]3 years ago
8 0
5=10x-3-6x=4x-3
8/4=x
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Of the fifth grade students 15/20 went to the book fair.Of the students who went to the book fair,12/16 bought at least one book
Vaselesa [24]

Answer:

\frac{9}{16}

Step-by-step explanation:

Let total number of students=x

Students went to the book fair:

Students went to book fair=\frac{15}{20}\times total\ number\ of\ students=\frac{15}{20}x

Students who bought book:

Students\ who\ bought\ book=\frac{12}{16}\times Number\ of\ students\ went\ to\ book\ fair=\frac{12}{16}\times \frac{15}{20}x=\frac{9}{16}x

Hence \frac{9}{16} of total students bought at least one book.

3 0
4 years ago
What is x and the measure of angle EHF<br><br>​
grin007 [14]

Answer:

x = 10, ∠ EHF = 110°

Step-by-step explanation:

7x and 11x are adjacent angles and sum to 180° , then

7x + 11x = 180

18x = 180 ( divide both sides by 18 )

x = 10

∠ EHF = 11x = 11(10) = 110°

8 0
3 years ago
Read 2 more answers
How's everyone doing?<br>(this used to be a math question but I just solved it myself)
guapka [62]

I'm good. Thx for asking bro! Have a splendid day :)

4 0
3 years ago
Evaluate -2 x^3 2y , if x = -3 and y = -1.<br><br> A. -12<br> B. 18<br> C. 12<br> D. -18
Vladimir [108]

Answer:

The answer is 108.

I hope this helps!

Step-by-step explanation:

(See picture for explanation!)

3 0
3 years ago
A man invests his savings in two accounts ,one paying6% and the other paying 10% simple interest per year. He puts twice as much
AnnyKZ [126]

Answer: he invested $46062.5 at 6% and $23031.25 at 10%

Step-by-step explanation:

Let x represent the amount which he invested in the account paying 6% interest.

Let y represent the amount which he invested in the account paying 10% interest.

He puts twice as much in the lower-yielding account because it is less risky.. This means that

x = 2y

The formula for determining simple interest is expressed as

I = PRT/100

Considering the account paying 6% interest,

P = $x

T = 1 year

R = 6℅

I = (x × 6 × 1)/100 = 0.06x

Considering the account paying 10% interest,

P = $y

T = 1 year

R = 10℅

I = (y × 10 × 1)/100 = 0.1y

His annual interest is $7370dollars. it means that

0.06x + 0.2y = 7370 - - - - - - - - - -1

Substituting x = 2y into equation 1, it becomes

0.06 × 2y + 0.2y = 7370

0.12y + 0.2y = 7370

0.32y = 7370

y = 7370/0.32

y = $23031.25

x = 2 × 23031.25

x = 46062.5

6 0
3 years ago
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