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expeople1 [14]
2 years ago
13

I will mark you as most Brillance if you help me get this right!

Mathematics
1 answer:
Dovator [93]2 years ago
8 0
5=10x-3-6x=4x-3
8/4=x
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A box of chocolates contains, on average, 12 pieces of chocolate. If the number of chocolates in each box never varies from the
marta [7]
The answer would be C. 36 
3 0
2 years ago
What is the solution set of {x | x < -3} ∩ {x | x > 5}
lozanna [386]
Any x in this set will be real numbers that are both less than -3 and greater than 5. But that's not possible, so this set is empty.
7 0
3 years ago
The radius of a spherical balloon is measured as 20 inches, with a possible error of 0.03 inch. Use differentials to approximate
soldi70 [24.7K]

Answer:

a) V = 33510.322\,in^{3}, b) A_{s} = 5026.548\,in^{2}, c) \% V = 0.450\,\%, \%A_{s} = 0.300\,\%.

Step-by-step explanation:

The volume and the surface area of the sphere are, respectively:

V = \frac{4}{3}\pi \cdot r^{3}

A_{s} = 4\pi \cdot r^{2}

a) The volume of the sphere is:

V = \frac{4}{3}\pi \cdot (20\,in)^{3}

V = 33510.322\,in^{3}

b) The surface area of the sphere is:

A_{s} = 4\pi \cdot (20\,in)^{2}

A_{s} = 5026.548\,in^{2}

c) The total differentials for volume and surface area of the sphere are, respectively:

\Delta V = 4\pi\cdot r^{2}\,\Delta r

\Delta V = 4\pi \cdot (20\,in)^{2}\cdot (0.03\,in)

\Delta V = 150.796\,in^{3}

\Delta A_{s} = 8\pi\cdot r \,\Delta r

\Delta A_{s} = 8\pi \cdot (20\,in)\cdot (0.03\,in)

\Delta A_{s} = 15.080\,in^{2}

Relative errors are presented hereafter:

\%V = \frac{\Delta V}{V}\times 100\%

\%V = \frac{150.796 \,in^{3}}{33510.322\,in^{3}}\times 100\,\%

\% V = 0.450\,\%

\% A_{s} = \frac{\Delta A_{s}}{A_{s}}\times 100\,\%

\% A_{s} = \frac{15.080\,in^{2}}{5026.548\,in^{2}}\times 100\,\%

\%A_{s} = 0.300\,\%

4 0
3 years ago
What is the distributative answer to 85 divided by 5 answer
andrew11 [14]
85/5
(50+35)/5
50/5 + 35/5
10+7=17
6 0
2 years ago
100 = 10 to the power of what
Greeley [361]

Answer:

10 to the power of 2

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
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