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Paul [167]
3 years ago
8

900 × 129 please help me

Mathematics
2 answers:
Anastasy [175]3 years ago
3 0
900 × 126= 116,100. Hoped this helped.
Wewaii [24]3 years ago
3 0
He's right it's 116,100
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Two consecutive whole numbers the square root of 76 lies between
Bas_tet [7]
8^2 = 64
9^2 = 81

Therefor the square root of 76 will lie somewhere between 8 and 9
7 0
4 years ago
Let f(x) = (x − 3)−2. Find all values of c in (1, 7) such that f(7) − f(1) = f '(c)(7 − 1). (Enter your answers as a comma-separ
Sidana [21]

Answer:

This contradicts the Mean Value Theorem since there exists a c on (1, 7) such that f '(c) = f(7) − f(1) (7 − 1) , but f is not continuous at x = 3

Step-by-step explanation:

The given function is

f(x)=(x-3)^{-2}

When we differentiate this function with respect to x, we get;

f'(x)=-\frac{2}{(x-3)^3}

We want to find all values of c in (1,7) such that f(7) − f(1) = f '(c)(7 − 1)

This implies that;

0.06-0.25=-\frac{2}{(c-3)^3} (6)

-0.19=-\frac{12}{(c-3)^3}

(c-3)^3=\frac{-12}{-0.19}

(c-3)^3=63.15789

c-3=\sqrt[3]{63.15789}

c=3+\sqrt[3]{63.15789}

c=6.98

If this function satisfies the Mean Value Theorem, then f must be continuous on  [1,7] and differentiable on (1,7).

But f is not continuous at x=3, hence this hypothesis of the Mean Value Theorem is contradicted.

 

3 0
3 years ago
(-8p^3+9p^2q-5pq^2) +(8p^3-pq+5q^2)=(−8p
olchik [2.2K]

(-8p^3+9p^2q-5pq^2) +(8p^3-pq+5q^2)=\\=-8p^3+9p^2q-5pq^2 +8p^3-pq+5q^2=\\=9p^2q-5pq^2-pq+5q^2

4 0
3 years ago
I used the rule add 4 , subtract 1 to generate a pattern. the first term in the pattern is 5. how can i write a number that coul
ozzi
5 + 4 - 1 = 7

7 + 4 - 1 = 10

10 + 4 - 1 = 13

And so on
5 0
3 years ago
For the function g defined below, a is a constant and g(4)=8. What is the value of g(-4)?
Travka [436]

I hope this helps!


g(x)= ax^2 + 24


g(4)= 8, g(-4)


a(4^2) + 24 = 8


16a+24= 8

-24 -24

16a = -16

a = -1

3 0
4 years ago
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