The standard form of the equation of a circle is (x−5)2+(y−6)2=1.

Mathematics

1 answer:

Crank3 years ago

3 0

Answer:

(A) $x^2+y^2-10x-12y+60=0$

Step-by-step explanation:

The standard form of the equation of a circle is given as:

$(x-5)^2+(y-6)^2=1$

Simplifying the above given equation, we get

$x^2+25-10x+y^2+36-12y=1$

$x^2+y^2-10x-12y+36+25=1$

$x^2+y^2-10x-12y+61=1$

$x^2+y^2-10x-12y+60=0$

which is the required general form of the equation.

Hence, option A is correct.

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3 years ago

If a cube has a volume of 9 feet and a shelf has a height of 27 inches, can the cube fit in the shelf?

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2 years ago

Read 2 more answers

In △ABC, point D∈ AB with AD:DB=5:3, point E∈ BC so that BE:EC=1:4. If AABC=40 in2, find AADC, ABDC, and ACDE.

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Please, see the attached files.

Thanks.