Answer:
-19
Step-by-step explanation:
Evaluate -x^2 - 5 x y + 5 y^3 where x = -2 and y = -1:
-x^2 - 5 x y + 5 y^3 = -(-2)^2 - -2 (-5) + (-1)^3×5
(-2)^2 = 4:
-4 - -5 (-2) + 5×(-1)^3
(-1)^3 = -1:
-4 - -5 (-2) + 5×-1
-5 (-2) = 10:
-4 - 10 - 5
-4 - 10 - 5 = -(4 + 10 + 5):
-(4 + 10 + 5)
| 1 | 0
| | 5
+ | | 4
| 1 | 9:
Answer: -19
7x^2 - 32x - 60
Factor by grouping,
(x - 6) (7x + 10)
The interquartile range is 20 you take Q3 in the graph which is 30 and the Q1 in the graph which is 10 then you subtract Q3-Q1 so 30-10 and get 20
The height of the tide after eight hours is 16 feet.
<h3>How to illustrate the function?</h3>
From the information given, the function is given as 5cos (π/4)t + 11.
In this case, the time is given as eight hours. This will be:
f(8) = 5 × cos (π/4) × 8 + 11
f(8) = 5 × cos(2π) + 11
= (5 × 0.999) + 11
= 16 feet
The height is 16 feet.
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