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wariber [46]
3 years ago
8

Stan ran 4 and StartFraction 7 Over 10 EndFraction miles, which was 1 and StartFraction 3 Over 10 EndFraction fewer miles than M

att ran. Four students wrote and solved equations to find m, the number of miles that Matt ran. Which student wrote and solved the equation correctly?
Mathematics
1 answer:
victus00 [196]3 years ago
7 0

Answer:

6 miles

Step-by-step explanation:

From the above question:

Stan ran 4 and StartFraction 7 Over 10 EndFraction miles

The number of miles stan ran =

4 7/10 miles

We are also told that this number of miles was 1 and StartFraction 3 Over 10 EndFraction fewer miles than Matt ran.

Let the number of miles Matt ran = m

Hence,

4 7/10 miles = m - 1 3/10

m = 4 7/10 + 1 3/10

m = (4 + 1) + ( 7/10 + 3/10)

m = 5 + (7 + 3/10)

m = 5 + (10/10)

m = 5 + 1

m = 6 miles

Therefore, the number rod miles Matt ran was 6 miles

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Can someone help me figure out this
QveST [7]

Answer:

YES

Step-by-step explanation:

The criterion for formation of a triangle is that the sum of any 2 sides should be greater than or equal to the third side

So, we will test it for all 3 sides

7.4 + 12.5 ≥ 19.9

TRUE

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4 0
3 years ago
Read 2 more answers
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I know it is in standard form because there are no more like terms.

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7 0
2 years ago
Trials in an experiment with a polygraph include 97 results that include 23 cases of wrong results and 74 cases of correct resul
o-na [289]

Answer:

H0:p= 0.80                 H1: p< 0.80  one tailed test

Step-by-step explanation:

We state the null and alternative hypotheses as that the results are 80 % against the claim that the results are less than 80%.

H0:p= 0.80                 H1: p< 0.80  one tailed test

p2= 0.8 , p1= 74/97= 0.763

q1= 1-0.763= 0.237    q2= 0.2

The level of significance is 0.05 .

The Z∝= ±1.645 for ∝= 0.05

The test statistic used here is

Z= p1-p2/ √pq/n

Putting the values:

Z= 0.763 -0.8 / √ 0.8*0.2/97

z= -0.037/ 0.0406

z= -0.9113

The Z∝ = ±1.645 for ∝= 0.05 for one tailed test.

As the calculated value  does not fall in the critical region  we fail to reject the null hypothesis. There is not sufficient evidence to support  the claim that such polygraph results are correct less than 80% of the time.

Using the normal probability table.

P (Z <  -0.9113)= 1- P(z= 0.9311) = 1- 0.8238= 0.1762

If P- value is smaller than the significance level reject H0.

0.1762> 0.005  Fail to reject H0.

8 0
4 years ago
If x = 9, what is the value of 6(x - 2)?
balandron [24]

Answer: 42

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3 0
2 years ago
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H = vt - 16t^2, solve for v
Sophie [7]
H=vt-16t²
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4 0
4 years ago
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