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wariber [46]
3 years ago
8

Stan ran 4 and StartFraction 7 Over 10 EndFraction miles, which was 1 and StartFraction 3 Over 10 EndFraction fewer miles than M

att ran. Four students wrote and solved equations to find m, the number of miles that Matt ran. Which student wrote and solved the equation correctly?
Mathematics
1 answer:
victus00 [196]3 years ago
7 0

Answer:

6 miles

Step-by-step explanation:

From the above question:

Stan ran 4 and StartFraction 7 Over 10 EndFraction miles

The number of miles stan ran =

4 7/10 miles

We are also told that this number of miles was 1 and StartFraction 3 Over 10 EndFraction fewer miles than Matt ran.

Let the number of miles Matt ran = m

Hence,

4 7/10 miles = m - 1 3/10

m = 4 7/10 + 1 3/10

m = (4 + 1) + ( 7/10 + 3/10)

m = 5 + (7 + 3/10)

m = 5 + (10/10)

m = 5 + 1

m = 6 miles

Therefore, the number rod miles Matt ran was 6 miles

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3 years ago
Solve 4.62 + (−12.3).<br><br> 56.83<br> 5.85<br> −7.68<br> −16.92
ikadub [295]

The sum of the given decimal numbers is -7.68

<h3>Sum of decimal numbers</h3>

Decimal numbers are numbers that contains decimal points. Given the expression below;

4.62 + (−12.3).

Convert to fraction to have:

4.62 + (−12.3) = 462/100 - 123/10

Find the LCM

4.62 + (−12.3) = 462-1230/100

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Learn more on sum of numbers here; brainly.com/question/25734188

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Suppose that you earned a​ bachelor's degree and now​ you're teaching high school. The school district offers teachers the oppor
stepan [7]

Answer:

Step-by-step explanation:

Answer:

a. The amount that is saved at the expiration of the 5 year period is $22,769.20¢

b. The amount of interest is $2,769.20¢

Step-by-step explanation:

Since the amount that is deposited every year for a period of five years is $4,000 and the rate of the interest is 6.5%. We can always calculate the amount that is saved at the expiration of the five years.

    We will first state the formula for calculating the future value of annuity:-

      Future value of annuity =

                      P[\frac{(1 + r)^{t}-1 }{r}]

   Where P is the amount deposited per year.

   r is the rate of interest

   t is the time or period

 

    and in this case, the actual value of P = $4,000

      rate of interest, r is 6.5% = 0.065

      time, t is 5 years.

   Substituting e, we have:

   Fv of annuity =

                          4,000[\frac{(1 + 0.065)^{5}-1 }{0.065 }]

   = 4,000 × [((1.065)^5)- 1/0.065]

 = 4,000 × [(1.37 - 1)/0.065]

 = 4,000 × (0.37/0.065)

 = 4,000 × 5.6923

 = $22,769.20¢

a. Therefore the amount that is saved at the end of the five (5) years is $22,769.20¢

b. To find the interest, we will calculate the amount of deposit made during the period of five years and subtract the sum from the current amount that is saved ($22,769.29¢).

  Since I deposited 4,000 every year for five years, the total amount of deposit I made at the period =

       4,000 × 5 = $20,000

  The amount of interest is then = $22,769.20¢ - $20,000 = $2,769.20¢

3 0
3 years ago
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