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salantis [7]
2 years ago
11

If a cone has a volume of 121cm^3 and a radius of 5 cm, how tall is it

Mathematics
2 answers:
notsponge [240]2 years ago
6 0
(<span>used with a singular verb</span><span>) the systematic treatment of magnitude,relationships between figures and forms, and relations betweenquantities expressed <span>symbolically</span></span>
Sladkaya [172]2 years ago
4 0

Answer:

The height of the cone is 4.62 cm.

Step-by-step explanation:

Since, the volume of a cone is,

V=\frac{1}{3} \pi r^2h

Where, r is the radius of the cone,

h is its height,

Here, V = 121 cm³ and r = 5 cm,

Thus, by substituting the values,

121=\frac{1}{3}\pi (5)^2 h

121=\frac{1}{3}\times \frac{22}{7} (25)h

\implies h = \frac{121\times 21}{22\times 25}=\frac{2541}{550}=4.62

Hence, the height of the cone is 4.62 cm.

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Since we have that the slope is m = 7/9 and the y-intercept is b = 12, we can write the equation of the line in slope-intercept form:

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to find three coordinate points, we can use arbitrary values on x to get the y-coordinate. To make things easier, let's use x = 9, 18 and 27:

\begin{gathered} x=9 \\ \Rightarrow y=\frac{7}{9}(9)+12=7+12=19 \\ x=18 \\ \Rightarrow y=\frac{7}{9}(18)+12=7(2)+12=14+12=26 \\ x=27 \\ \Rightarrow y=\frac{7}{9}(27)+12=7(3)+12=21+12=33 \end{gathered}

therefore, the line with slope m = 7/9 and y-intercept 12 passes through the three points (9,19), (18,26) and (27,33)

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