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3 years ago

Estimate the rate of change of the graphed function over the interval -4 ≤ x ≤ 0

Mathematics

1 answer:

Andrews [41]3 years ago

8 0

We need the graph to answer.

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joe runs 8.75 times around a track in 1,125.803 seconds. If one lap around the track is 420.3 meters, which is the best estimate

nikklg [1K]

8.75 x 420.3 = 3677.625 m
3677.625/1125.803 = 3.266668 ft/sec

7 0

4 years ago

A toy rocket launched into the air has a height ( h feet) at given time ( t seconds) as h= -16^2+160t until it hits the ground.

Gennadij [26K]

Answer:

$t = \frac{53}{32}$

Step-by-step explanation:

$h=\:-16^2+160t$

$9=\:-16^2+160t$ $substitute$

$-16^2+160t=9$

$-256+160t=9$

$-256+160t+256=9+256$

$160t=265$

$\frac{160t}{160}=\frac{265}{160}$

$t=\frac{53}{32}$

At $\frac{53}{32}$ seconds it is at a height of 9 ft.

4 0

3 years ago

I need help finding the factor!<br> please

irina1246 [14]

Answer:

(x-8) (x-4)

Step-by-step explanation:

x^2 -12x +32

What two numbers multiply to 32 and add to -12

-8*-4 = 32

-8-4 = -12

(x-8) (x-4)

5 0

4 years ago

Read 2 more answers

I really need this done today please help PLEAASSSEEE

Fantom [35]

Answer:

A and C

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Mathematics please help...

galben [10]

Answer:

the answer is B

Step-by-step explanation:

area of the minor arc is teter all over 360 times 2 pie r square.

that is

$\frac{?}{360} \times 2\pi {r}^{2}$

= but because the question said for length AB, youvhave to use only one radius.

$\frac{160}{360} \times 2 \times \pi \times 9$

You the use 40 to cancel 160 and 360 to get 4 all over 9 times 2 pie times 9.

$\frac{4}{9} \times 2 \times \pi \times 9$

You then cancel 9 with 9 to get 4 times 2 times pie

$4 \times 2 \times \pi$

this is equal to

$8\pi$

3 0

3 years ago