All categories

3 years ago

Simplify the expressions:

Mathematics

1 answer:

alex41 [277]3 years ago

8 0

Answer:

1. -x³

2. m²

3. -1.5t⁷

Step-by-step explanation:

x⁶^½ = +/- x³

Since x is negative, postive square root would be -x³

m⁴^½ = +/- m²

Positive square root is m²

t¹⁷^½ = +/- t⁷

Since t is negative, postive square root would be -t⁷

1.5 × -t⁷ = -1.5t⁷

You might be interested in

The first step when dividing 9m2 − 4m − 6 by 3m is shown. Which could be the next step? 3m − − 3m − − 3m − − 3m − −

Agata [3.3K]

Given:

Consider the below picture attached with this question.

The given expression is:

$\dfrac{9m^2}{3m}-\dfrac{4m}{3m}-\dfrac{6}{3m}$

To find:

The next step.

Solution:

We have,

$\dfrac{9m^2}{3m}-\dfrac{4m}{3m}-\dfrac{6}{3m}$

Cancel out the common factors.

$=3m-\dfrac{4}{3}-\dfrac{2}{m}$

Therefore, the correct option is D.

8 0

2 years ago

Among the career home run leaders for Major League Baseball, hank aaron has 181 fewer than twice the number of chipper Jones. Ha

adoni [48]

Answer: He has 287 home runs

Step-by-step explanation:

Let's define:

H = home runs of Hank

J = home runs of Jones.

We know that:

H = 2*J - 181

H = 755

Then we can replace the second equation into the first one:

755 = 2*J - 181

(755 - 181)/2 = J

287 = J

6 0

2 years ago

Suppose a change of coordinates T:R2→R2 from the uv-plane to the xy-plane is given by x=e−2ucos(5v), y=e−2usin(5v). Find the abs

anzhelika [568]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The solution is $\frac{\delta (x,y)}{\delta (u, v)} | = 10e^{-4u}$

Step-by-step explanation:

From the question we are told that

$x = e^{-2a} cos (5v)$

and $y = e^{-2a} sin(5v)$

Generally the absolute value of the determinant of the Jacobian for this change of coordinates is mathematically evaluated as

$| \frac{\delta (x,y)}{\delta (u, v)} | = | \ det \left[\begin{array}{ccc}{\frac{\delta x}{\delta u} }&{\frac{\delta x}{\delta v} }\\\frac{\delta y}{\delta u}&\frac{\delta y}{\delta v}\end{array}\right] |$

$= |\ det\ \left[\begin{array}{ccc}{-2e^{-2u} cos(5v)}&{-5e^{-2u} sin(5v)}\\{-2e^{-2u} sin(5v)}&{-2e^{-2u} cos(5v)}\end{array}\right] |$

$Let \ a = -2e^{-2u} cos(5v), \\ b=-2e^{-2u} sin(5v),\\c =-2e^{-2u} sin(5v),\\d=-2e^{-2u} cos(5v)$

$\frac{\delta (x,y)}{\delta (u, v)} | = |det \left[\begin{array}{ccc}a&b\\c&d\\\end{array}\right] |$

=> $\frac{\delta (x,y)}{\delta (u, v)} | = | a * b - c* d |$

substituting for a, b, c,d

=> $\frac{\delta (x,y)}{\delta (u, v)} | = | -10 (e^{-2u})^2 cos^2 (5v) - 10 e^{-4u} sin^2(5v)|$

=> $\frac{\delta (x,y)}{\delta (u, v)} | = | -10 e^{-4u} (cos^2 (5v) + sin^2 (5v))|$

=> $\frac{\delta (x,y)}{\delta (u, v)} | = 10e^{-4u}$

7 0

2 years ago

If each group has the greatest possible number of club members,

Mars2501 [29]

So anybody know the answer yet cuz i don’t

7 0

2 years ago

Find JL if JK = 17 - x, KL = 2x - 7, and K is the midpoint of JL

Murljashka [212]

I'm assuming that the line is JKL in order of the points from left to right.

JK + KL = JL
(17-x) + (2x-7) = JL
Simplify.
10-x = JL

6 0

3 years ago