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notka56 [123]
4 years ago
6

Write an equation for the parabola with a vertex at the origin and focus of (4,0)

Mathematics
1 answer:
kiruha [24]4 years ago
8 0
We will first plot those points to see what type of parabola this is.  If the vertex is at (0, 0) and the focus is at (4, 0), this will be a parabola that opens to the right, since the parabola always curves around the focus.  The standard form for a parabola of this type is (y-k)^2=4p(x-h), where h and k are the coordinates of the vertex, and p is the distance between the vertex and the focus.  Our h and k are both 0, and our p distance is 4: (y-0)^2=4*4(x-0).  Cleaning that up a bit we get y^2=16x.  And there you go!
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Given:

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To find:

The value of matrix C.

Solution:

Let A=\begin{bmatrix}-18&3&5\end{bmatrix},B=\begin{bmatrix}-22&1&12\end{bmatrix}. Then the given equation can be rewritten as

A-C=B

-C=B-A

C=-(B-A)

C=A-B

On substituting the values of the matrices, we get

C=\begin{bmatrix}-18&3&5\end{bmatrix}-\begin{bmatrix}-22&1&12\end{bmatrix}

C=\begin{bmatrix}-18-(-22)&3-1&5-12\end{bmatrix}

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Therefore, the correct option is C.

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