Answer:
<h2>(f · g)(x) is odd</h2><h2>(g · g)(x) is even</h2>
Step-by-step explanation:
If f(x) is even, then f(-x) = f(x).
If g(x) is odd, then g(-x) = -g(x).
(f · g)(x) = f(x) · g(x)
Check:
(f · g)(-x) = f(-x) · g(-x) = f(x) · [-g(x)] = -[f(x) · g(x)] = -(f · g)(x)
(f · g)(-x) = -(f · g)(x) - odd
(g · g)(x) = g(x) · g(x)
Check:
(g · g)(-x) = g(-x) · g(-x) = [-g(x)] · [-g(x)] = g(x) · g(x) = (g · g)(x)
(g · g)(-x) = (g · g)(x) - even
Answer:
g(1) = 0
=
lgn= ) +m
g(n) = g(n - 1) +n
=
-
n
g(2) =12
Step-by-step explanation:
12345678910
You would have to Find the GCF
Answer:
rip Pop we aint neva gettin cool with the opps
190000
hope this helps
Step-by-step explanation:
