Prove that (2n+1)^2 - (2n+1)^2 is a multiple of 8 for all positive integer values of n
1 answer:
Answer:
(2n + 1)[(2n + 1) � 1]
(2n + 1)(2n + 1 � 1)
(2n + 1)(2n), or 2n(2n + 1)
2n is an EVEN NUMBER, and adding 1 to an even number creates an ODD number
Therefore, 2n(2n+1)=EVEN NUMBER ODD NUMBER=EVEN NUMBER
Step-by-step explanation:
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