Prove that (2n+1)^2 - (2n+1)^2 is a multiple of 8 for all positive integer values of n
1 answer:
You might be interested in
Answer:
=2
Step-by-step explanation:
We have to make the fractions equal so we can add them
1 ×4= 1
×3=
1+
=2
Answer:
The roots are: √11 + 2 and -√11 + 2
Explanation:
First, we would put the equation in the standard form which is as follows:
ax² + bx + c = 0
This can be done as follows:
x² - 4x + 4 - 11 = 0
x² - 4x - 7 = 0
By comparison:
a = 1
b = -4
c = -7
Now, to get the roots, we would use the quadratic equation shown in the attached image.
By substitution, we would find that:
either x = √11 + 2
or x = -√11 + 2
Hope this helps :)
The roots are: √11 + 2 and -√11 + 2
Explanation:
First, we would put the equation in the standard form which is as follows:
ax² + bx + c = 0
This can be done as follows:
x² - 4x + 4 - 11 = 0
x² - 4x - 7 = 0
By comparison:
a = 1
b = -4
c = -7
Now, to get the roots, we would use the quadratic equation shown in the attached image.
By substitution, we would find that:
either x = √11 + 2
or x = -√11 + 2
Hope this helps :)