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Ipatiy [6.2K]
3 years ago
13

If a block of wood measuring 5 cm x 10 cm x 3 cm has a mass of 100 g, could it be birch wood?

Mathematics
1 answer:
Inga [223]3 years ago
5 0

Answer:

It very well could be

Step-by-step explanation:

It could be any type of wood, it doesn't matter weight, volume, or size

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Evaluate the expression 11C3
butalik [34]
Evaluating the expression 11C3 is very simple to do. 

If you are assuming that C is the notation for the combination. 
             11!
11C3= ____
     
            3!(11-3)!
3 0
3 years ago
CAN SOMEONE PLEASE HEALP MEEEEEEE A rectangle has an area of 24 square units and a side length of 2 3/4 units. Find the other si
Trava [24]

Answer:

12

Step-by-step explanation:

Using the formula

A=wl

Solving for l

1=a/w=24/2=12

3 0
3 years ago
In 2011, Americans spent approximately $50.9 billion on their pets. Of this amount, $14.1 billion was for veterinarian bills. Wh
alex41 [277]

Answer: The percent of the total was spent on veterinarian bills is 27.70% ( approx).

Step-by-step explanation:

Given, In 2011, Americans spent approximately $50.9 billion on their pets.

i.e. Total amount they spent on pets = $50.9 billion

Amount spent for veterinarian bills.  = $14.1 billion was for veterinarian bills.

Then, the percent of the total was spent on veterinarian bills would be :

\dfrac{\text{Amount spent for veterinarian bills. }}{\text{Total amount they spent on pets}}\times100\\\\=\dfrac{14.1}{50.9}\times100\\\\=27.7013752456\approx27.70\%

Hence, the percent of the total was spent on veterinarian bills is 27.70% (approx).

5 0
3 years ago
helppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppp
Alex787 [66]
B then C
i have a 20 character limit so i’m just typin here
6 0
2 years ago
The 65 students in a classical music lecture class were polled, with the following results: 37 like Wolfgang Amadeus Mozart 36 l
Anna35 [415]

Answer:

a) 25

b) 30

c) 10

d) Not Mozart, 6

e) 2

Step-by-step explanation:

We use a Venn Diagram to solve this question.

I am going to say that:

A are the students who like Mozart.

B are the students who like Beethoven

C are the students who like Haydn.

We have that:

A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)

In which a are those who only like Mozart, (A \cap B) are those who like Mozart and Beethoven, (A \cap C) are those who like Mozart and Haydn and (A \cap B \cap C) are those who like all three of them.

By the same logic, we have that:

B = b + (A \cap B) + (B \cap C) + (A \cap B \cap C)

C = c + (B \cap C) + (A \cap C) + (A \cap B \cap C)

We start finding these values from the intersection:

8 like all three composers

This means that A \cap B \cap C = 8

14 like Beethoven and Haydn

This means that:

(B \cap C) + (A \cap B \cap C) = 14

So

B \cap C = 6

21 like Mozart and Haydn

This means that:

(A \cap C) + (A \cap B \cap C) = 21

Then

A \cap C = 13

14 like Mozart and Beethoven

This means that:

(A \cap B) + (A \cap B \cap C) = 14

A \cap B = 6

31 like Franz Joseph Haydn

This means that C = 31. So

C = c + (B \cap C) + (A \cap C) + (A \cap B \cap C)

31 = c + 6 + 13 + 8

c = 4

36 like Ludwig van Beethoven

This means that B = 36

So

B = b + (A \cap B) + (B \cap C) + (A \cap B \cap C)

36 = b + 6 + 6 + 8

b = 16

37 like Wolfgang Amadeus Mozart

This means that A = 37. Then

A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)

37 = a + 6 + 13 + 8

a = 10

a. exactly two of these composers?

(A \cap B) + (A \cap C) + (B \cap C) = 6 + 13 + 6 = 25

b. exactly one of these composers?

a + b + c = 10 + 16 + 4 = 30

c. like only Mozart?

a = 10

d. like Beethoven and Haydn, but not Beethoven?

I will use not Mozart.

So B \cap C = 6

Not Mozart, 6.

e. like none of these composers?

At least 1:

(A \cup B \cup C) = a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 10 + 16 + 4 + 6 + 13 + 6 + 8 = 63

The total is 65

So 65 - 63 = 2 like none of these composers

4 0
3 years ago
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