All categories

2 years ago

Suma cyfr szukanej liczby dwucyfrowej jest równa 12. Jeżeli cyfry tej liczby przestawimy, to

Mathematics

1 answer:

polet [3.4K]2 years ago

7 0

Answer:

yes

Step-by-step explanation:

You might be interested in

Raportul a doua catete ale unui triunghi dreptunghic este de 3 supra 7,iar inaltimea este de 42cm.Aflati inaltimea,catetele,ipot

Basile [38]

Answer:

could you write in in english

Step-by-step explanation:

6 0

2 years ago

Train A departs station one traveling at 75 mph. Train N departs station two 30 minutes later traveling at 45 mph. The stations

Paul [167]

Answer:B

Step-by-step explanation:

7 0

2 years ago

H(x) = x^2+6 g(x) = 8x-5 <br><br> show that hg(x)=19 simplifies to 16x^2 - 20x + 3 = 0

Studentka2010 [4]

Answer:

h(x)=x²+6 and g(x)=8x-5

prove that hg(x)=19

Step-by-step explanation:

step 1: hog(x)=h[g(x)]

step 2: h(8x-5)

step 3: h(8x-5)= (8x-5)²+6

step 4: (8x-5)(8x-5)+6

step 5: 16x² +15x +6

6 0

2 years ago

Solve the equation for x.<br> – 1/2x – 3 = 4

Nana76 [90]

Answer:

x = -4

Step-by-step explanation:

Multiply both sides by 2. Move constant to the right-hand side and change the sign. Add the numbers. And change the signs on both sides of the equation.

5 0

3 years ago

Read 2 more answers

Grasshoppers are distributed at random in a large field according to a Poisson process with parameter a 5 2 per square yard. How

HACTEHA [7]

In this question, the Poisson distribution is used.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Parameter of 5.2 per square yard:

This means that $\mu = 5.2r$ , in which r is the radius.

How large should the radius R of a circular sampling region be taken so that the probability of finding at least one in the region equals 0.99?

We want:

$P(X \geq 1) = 1 - P(X = 0) = 0.99$

Thus:

$P(X = 0) = 1 - 0.99 = 0.01$

We have that:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-5.2r}*(5.2r)^{0}}{(0)!} = e^{-5.2r}$

Then

$e^{-5.2r} = 0.01$

$\ln{e^{-5.2r}} = \ln{0.01}$

$-5.2r = \ln{0.01}$

$r = -\frac{\ln{0.01}}{5.2}$

$r = 0.89$

Thus, the radius should be of at least 0.89.

Another example of a Poisson distribution is found at brainly.com/question/24098004

3 0

2 years ago