So the length is 4*28=112mm
The width would be calculated like this:
you draw an equilateral triangle in the middle with sides or 2r(56mm). The based on pythagorean theorem u know that
h=rad(56^2-28^2)=48.497
28+28+h=104.497
The area would be S=l*w which is 11703.7113mm
Answer:
f(x) = -2x+5
f(x+h) = -2x -2h +5
g(x) = -4x-2
g(x+h) = -4x -4h -2
h(x) = 4x^2+1
h(x+h) = 4(x+h)^2 +1 = 4x^2 +8xh + 4h^2 +1
Q(x) = -3x^2 +4
Q(x+h) = -3(x+h)^2 +4 = -3x^2 -3h^2 -6xh + 4
Answer:
1/4
Step-by-step explanation:
Answer:
10,404/334,084
Step-by-step explanation:
Given the polynomial
289r^2 - 102r + c
We are to find the value of c that will make it a perfect square
Divide through by 289
289r²/289 - 102r/289 + c/289
Half of the coefficient of r is 1/2(102/289)
Half of the coefficient of r = 102/578
Square the result
r² = (102/578)²
r² = 10,404/334,084
Hence the required constant is 10,404/334,084