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lora16 [44]
2 years ago
7

Solve for a side triangles please help it’s urgent please answer

Mathematics
1 answer:
rodikova [14]2 years ago
7 0

Answer:

AC ≈ 2.87

Step-by-step explanation:

Using the sine ratio in the right triangle

sin35° = \frac{opposite}{hypotenuse} = \frac{AC}{AB} = \frac{AC}{5}

Multiply both sides by 5

5 × sin35° = AC , thus

AC ≈ 2.87 ( to the nearest hundredth )

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If 15 men can do a piece of work in 30 days, in how many days can 10 men complete the same work?
Sav [38]

Answer:

45

Step-by-step explanation:

n/15=30

therefore n=450

hence n/10 = 45

3 0
2 years ago
Read 2 more answers
I do not understand
Vanyuwa [196]

\huge \sf༆ Answer ༄

Here's the solution ~

  • \sf \dfrac{5 {}^{6} }{5 {}^{1} }

  • \sf 5 {}^{6 - 1}

  • \sf {5}^{5}

8 0
2 years ago
Please help. solve for x
malfutka [58]

Step-by-step explanation:

Given,

Base of the triangle

2 \sqrt{6}

Hypotenuse of the triangle = 5

Height of the triangle = x

Therefore, According to Pythagoras Theorem,

{base}^{2}  +  {height}^{2}  =  {hypotenuse}^{2}

=  >  {(2 \sqrt{6)} }^{2}  +  {x}^{2}  =  {5}^{2}

=  > 24 +  {x}^{2}  = 25

=  >  {x}^{2}  = 25 - 24

=  >  {x}^{2}  = 1

=  > x =  \sqrt{1}

=  > x = 1

Hence, the required value of <u>x is 1.</u>

7 0
2 years ago
Le
juin [17]
Total age of pupils
= 12.7 x 10
= 127 years

127 - 11 - 10 - 12 - 11 - 14 - 13 - 14 - 16 = 26 ( total age of the other 2 pupils added together )

however, since the ninth pupil is two years younger,

26-2=24
24/2=12 ( age of ninth pupil )
12+2=14 ( age of tenth pupil )

thus, (a) 12 years old,
(b) 14 years old.
4 0
3 years ago
Need help on this problem plz
sergij07 [2.7K]

Answer:

The answer is no

Step-by-step explanation:

4 0
3 years ago
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