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hjlf
3 years ago
9

Hi!

Mathematics
1 answer:
Elina [12.6K]3 years ago
3 0

Answer:

404.09x cm³ (to 5 s.f.),

where x is the unknown height of the shape.

Step-by-step explanation:

Volume of the shape

= base area × height

= (large semicircle- small semicircle) × thickness of shape

Area of circle= \pi {r}^{2}

Area of semicircle= \frac{1}{2} (\pi)( {r}^{2} )

Diameter of small circle= 14

Radius= diameter ÷2

radius= 14 ÷2

radius = 7 cm

Area of small semicircle

=  \frac{1}{2} (\pi)( {7}^{2} ) \\  =  \frac{49}{2} \pi

Radius of large semicircle

= 35 ÷2

= 17.5 cm

Area of large semicircle

= \frac{1}{2} (\pi)( {17.5}^{2} ) \\  =  \frac{1225}{8} \pi

Base area of shape

= \frac{1225}{8}\pi  -  \frac{49}{2} \pi \\  =  \frac{1029}{8} \pi

Since the height if the shape is not given, I'm afraid I cant help you find the volume.

Let the height of the shape be x cm.

Volume of shape= \frac{1029x}{8} \pi \: cm^{3}

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10x+2/2=4x+.25 help please
d1i1m1o1n [39]

Answer:

x= 0.125

Step-by-step explanation:

4 0
2 years ago
Folds - Circle Cliffs, UT. Both monoclines and anticlines uplift and deform rock layers such that when eroded, certain ages of r
DIA [1.3K]

Answer:the relative ages of the rocks exposed in the circle cliff area are given below.

1. older rocks are exposed in the center and younger rocks in the flanking flatirons.

2. younger rocks are exposed in the center and older rocks in the flanking flatirons.

Step-by-step explanation: this is because whenever older rocks are exposed in circle cliffs, exposure occur at the center while younger rocks will be exposed in the flanking flatirons at this time.

2. But when younger rocks are exposed in contrast to the older rocks, these younger rocks are exposed at the center while the older ones receive exposure at the flanking flatirons.

Note that both cases interchange, exposure of a particular rock occur at the center and the next category of rock receive theirs at flanking flatirons.

7 0
3 years ago
Marisa gets paid $50 for 5 hours of work and charges an initial fee of $13
Vitek1552 [10]

Answer:

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Step-by-step explanation:

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3 years ago
Find the distance between the points <br> (-8,-6) and (4, 10)
never [62]

Answer:

d=20

Step-by-step explanation:

To find the distance between 2 points we use the distance formula

d = √(x2 - x1)²+(y2 - y1)²

The given points are (x1= -8, y1 = -6) and (x2 = 4, y2 = 10).

Substitute the given points into the distance formula.

d = √(4 + 8)²+(10 +6)²

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3 0
3 years ago
Jada solved the equation Negative StartFraction 4 over 9 EndFraction = StartFraction x over 108 EndFraction for x using the step
GalinKa [24]

Answer:

Jada should have multiplied both sides of the equation by 108.

Step-by-step explanation:

The question is incomplete. Find the complete question in the comment section.

Given the equation -4/9 = x/108, in order to determine Jada's error, we need to solve in our own way as shown:

Step 1: Multiply both sides of the equation by -9/4 as shown:

-4/9 × -9/4 = x/108 × -9/4

-36/-36 = -9x/432

1 = -9x/432

1 = -x/48

Cross multiplying

48 = -x

x = -48

It can also be solved like this:

Given -4/9 = x/108

Multiply both sides by 108 to have:

-4/9 * 108 = x/108 * 108

-4/9 * 108 = 108x/108

-432/9 = x

x = -48

Jada should have simply follow the second calculation by multiplying both sides of the equation by 108 as shown.

7 0
3 years ago
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