Please help me out:/

What the area of this shape

Rudiy27

Answer:it is 6,930

Step-by-step explanation:

3 0

3 years ago

PLEASE HELP 30 POINTS

mote1985 [20]

Answer: Maggie is 29 years old

Step-by-step explanation:

12*3=36

36-7=29

29 + 12 = 41

5 0

3 years ago

PLZ PLZ WITH EXPLANATION

Vadim26 [7]

Answer:

For the first 2 pages, you will want to count how many sides and angles for the stated figure above. Then you want to figure out what other figures that are related to the figure stated above. i.e. a square is a rectangle but not all rectangles are squares. On the last page you want to figure out what is the figure's name and other names that are related/same on the figure's original name. And lastly for part II you want to do the same thing for page 1 and 2, but instead you want to compare and contrast the 2 figures stated above. i.e. Parallelograms and Trapezoids.

Step-by-step explanation:

Hope this helps! :)

8 0

2 years ago

Joel’s veterinarian tells him that he can give his dog 11 5/8 mg of Benadryl for relief of his dogs allergies. Joel’s dog weighs

Sav [38]

Step-by-step explanation:

Given that,

The dosage of Benadryl for Dog is $11\dfrac{5}{8}\ mg$

Weight of Joel's Dog is $15\dfrac{1}{2}\ \text{pounds}$

(a) Benadryl dosage per pound for Joel’s dog is calculated as :

$\dfrac{11\dfrac{5}{8}}{15\dfrac{1}{2}}=\dfrac{\dfrac{11\times 8+5}{8}}{\dfrac{15\times 2+1}{2}}\\\\=\dfrac{\dfrac{93}{8}}{\dfrac{31}{2}}\\\\=\dfrac{93}{8}\times \dfrac{2}{31}\\\\=0.75\ \text{dosage per pound}$

(b) If the weight of the Dog is 12 pounds, it means

$\dfrac{11\dfrac{5}{8}}{12}\ \text{dosage per pounds}\\\\=\dfrac{\dfrac{93}{8}}{12}\\\\=\dfrac{93}{8}\times \dfrac{1}{12}\\\\=0.968\ \text{dosage per pounds}$

Therefore, this is the required solution.

3 0

2 years ago

a) Suppose f"(z) exists on an interval I and f(s) has a zero at three distinct points a < b< c on I. Show there is a pbint

Fynjy0 [20]

Answer:

We can find a root in the average point (a+b+c)/3

Step-By-Step Explanation:

We can use the Rolle Theorem. Since f is two times deribable on both [a,b] and [b,c], then there exists points x in (a,b) and y in (b,c) such that f'(x) = f'(y) = 0. Now, again by using Rolle Theorem, since f' is derivable in [x,y] (because it is a closed interval in I), then there exists s in [x,y] such that f''(s) = 0. This proves a.

The cube (x-a)(x-b)(x-c) has 3 roots, a, b and c and it is two times derivable because it is a polynomial. Hence we can use (a) to ensure that there is a root on I. Nevertheless, we can try to find the root manually:

f'(x) = (x-b)(x-c)+(x-a)(x-c)+(x-a)(x-b)

f''(x) = (x-c)+(x-b)+(x-c)+(x-a)+(x-b)+(x-a) = 2(x-a)+2(x-b)+2(x-c) = 2( (x-a) + (x-b) + (x-c) ) = 6x - 2 (a+b+c).

We want x such that

6x - 2(a+b+c) = 0, or, equivalently,

3x - (a+b+c) = 0

Hence

x = (a+b+c)/3

Is a root of f'' in I.

3 0

3 years ago