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madreJ [45]
3 years ago
10

A community hall is in the shape of a cuboid the hall is 40m long 15m high and 3m wide. 10 litre paint covers 25m squared costs

?10. 1m squared floor tiles costs ?3. Work out the total costs of tiles and paints
Mathematics
1 answer:
Darina [25.2K]3 years ago
6 0

Answer:

Total cost for tiles and paints is $924.  

Step-by-step explanation:

We have been given that a community hall is in the shape of a cuboid. The hall is 40m long 15m high and 3m wide.

The paint will be required for 4 walls and ceiling.

Let us find area of walls and ceiling.

\text{Area of walls and ceiling}=(2*40*15)+(2*3*15)+(40*3)

\text{Area of walls and ceiling}=1200+90+120

\text{Area of walls and ceiling}=1410

Therefore, the area of walls and ceiling is 1410 square meters.

Given: Cost for 10 litre of paint is $10 and 10 litre paint covers 25 square meter. Therefore,  

\text{ The total painting cost}=10*(\frac{1410}{25})

\text{ The total painting cost}=10*56.4=564

Therefore, the total painting cost is $564.  

Tiles will be required for floor. Let us find the area of floor.

\text{Area of floor} = 40*3\text{ square meters}

\text{Area of floor} =120\text{ square meters}

Given: 1m squared floor tiles costs $3. So,  

\text{Total cost for tiles} = 3*120 = 360

Therefore, the total tiles cost is $360.

Now let us find combined total cost of tiles and paint.

\text{Combined total cost}= 564+360 = 924

Therefore, the combined total cost of tiles and paint is $924.

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Between which two ordered pairs does the graph of f(x) = 1/2x2 + x – 9 cross the negative x-axis? (–6, 0) and (–5, 0) (–4, 0) an
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Between (-6,0) and (-5,0).

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3 0
3 years ago
The length of a rectangle is six times its width. If the area of the rectangle is 486 in 2 , find its perimeter.
seraphim [82]

w - width

6w - length

486 in² - area of the rectangle

(w)(6w) = 6w² - area of the rectangle

The equation:

6w² = 486     <em>divide both sides by 6</em>

w² = 81 → w = √81

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l = 6w → l = (6)(9) → l = 54 in

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<h3>Answer: The perimeter is 126in</h3>
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