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Mrac [35]
3 years ago
9

Are all integers rational numbers?

Mathematics
2 answers:
tino4ka555 [31]3 years ago
8 0

Answer:

yes

Step-by-step explanation:

all integers can be formed from the division of two other whole numbers.

Tcecarenko [31]3 years ago
4 0

Answer:

yes all integers are rational numbers

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The Martinez family went to the movies and paid $60 for two adult tickets and three children’s tickets. The Wright family consis
Pepsi [2]

Answer:

a = $13.5

Step-by-step explanation:

Let a = adult tickets

Let c = children tickets

Translating the word problem into an algebraic equation;

<u>For the Martinez family;</u>

2a + 3c = $60

<u>For the Wright family;</u>

3a + 5c = $95.5

Thus, the simultaneous equations are;

2a + 3c = $60 ..........equation 1

3a + 5c = $95.5 .........equation 2

We would use substitution method to solve;

From equation 2, we make a the subject of formula;

3a = 95.5 - 5c

a = (95.5 - 5c)/3

<em>Substituting the value of "a" into equation 1, we have;</em>

2[(95.5-5c)/3] + 3c = 60

Multiplying all through by 3;

2(95.5 - 5c) + 9c = 180

191 - 10c + 9c = 180

191 - c = 180

c = 191-180

c = $11

To find the value of a;

2a +3c = 60

<em>Substituting the value of "c" into the equation, we have;</em>

2a + 3(11) = 60

2a + 33 = 60

2a = 60 - 33

2a = 27

a = \frac{27}{2}

a = $13.5

<em>Therefore, the cost of an adult movie ticket is $13.5. </em>

5 0
3 years ago
I need the answer for 21
levacccp [35]

Answer:

h>13

Step-by-step explanation:

3 0
3 years ago
Help solve 4 and 5 please
Sloan [31]

Answer:

Step-by-step explanation:

4). a). If the diagonals of a parallelogram are congruent, then it must be a RECTANGLE.

b). If the diagonals of a parallelogram are perpendicular, then it must be a SQUARE.

c). If the diagonals of a parallelogram bisect the angles of the parallelogram, then it must be a RHOMBUS.

d). If the diagonals of a parallelogram are perpendicular and congruent, then it must be a SQUARE.

e). If a parallelogram has four congruent sides, then it must be a SQUARE.

5). Given quadrilateral SELF is a rhombus.

a). All sides of a rhombus are equal,

   Therefore, ES = EL = 25

b). Diagonals of a rhombus bisects the opposite angles,

   Therefore, m∠ELS = m∠FLS

    3x - 2 = 2x + 7

    3x - 2x = 7 + 2

    x = 9

c). Diagonals of the rhombus bisect the opposite angles, and adjacent angles are supplementary.

m∠ELF = 2(m∠ELS) = 2(2y - 9)

m∠LES = 2(m∠LEF) = 2(3y + 9)

And 2(2y - 9) + 2(3y + 9) = 180

(2y - 9) + (3y + 9) = 90

5y = 90

y = 18  

6 0
3 years ago
In how many ways can a committee of 2 men and 1 woman be formed from a group of 12 men and 12 ​women
worty [1.4K]
2 Men have to be picked from the 12 Men :   12 C 2
 
                                                                    = (12*11)/(2*1) = 66

1 Woman have to be picked from the 12 Women :   12 C 1
 
                                                                    = (12)/(1) = 12

Total Number of ways = 66 * 12 = 792

792 ways.
6 0
4 years ago
Can you help me for all three plzzzz
zimovet [89]
I hope this helps you!!

3 0
3 years ago
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