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Dmitrij [34]
3 years ago
13

Which answer choice you you choose?

Biology
2 answers:
Marrrta [24]3 years ago
8 0
Answer: A) it’s just the best answer from all those explanations
VashaNatasha [74]3 years ago
4 0

Answer:

A

Explanation:

It makes the most sense and if i remember that is a chain reaction.

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A mouse geneticist selected for increased 12-day litter weight (total weight of a litter of offspring 12 days after birth) in a
wlad13 [49]

Answer:

12-day litter weight is a trait that has an important genetic influence and therefore also a high response to selection

Explanation:

Heritability is a statistical measure of how much of the variation in a given trait can be attributed to genetic differences and how much of trait variation is due to environmental factors. A heritability value close to 1 indicates that almost all of the variability is due to genetic factors, while being poorly influenced by environmental factors. In this case, 12-day litter weight is a trait that exhibits an important genetic component (i.e., a high heritability value), thereby the correlation between parent and offspring will be high and lines selected for this trait will show a high response to selection.

4 0
3 years ago
How many nucleotide bases are there in 24 codons? Show work, circle final answer
JulsSmile [24]

Answer:

The nucleotide triplet that encodes an amino acid is called a codon. Each group of three nucleotides encodes one amino acid. Since there are 64 combinations of 4 nucleotides taken three at a time and only 20 amino acids, the code is degenerate (more than one codon per amino acid, in most cases).

3 0
3 years ago
The part of the eye that closes and opens to let light in is the________ .
irga5000 [103]

Hello There!

This is called the "IRIS"

The iris is the colored part of they eye and it's responsible for focusing light onto the cornea.

7 0
3 years ago
Read 2 more answers
why are individuals with an extra chromosome 21, down syndrome, more numerous than individuals with an extra chromosome 3?
givi [52]

Extra copies of the other chromosomes are probably fatal to the developing embryo that's why individuals with extra chromosome 21 are more numerous than extra chromosomes 3 or 16.

The term "aneuploidy" in genetics refers to the alteration in chromosomal number 23, which can result in hereditary disorders. An individual is said to be aneuploid if they have fewer chromosomes than the wild or euploid type due to an additional or missing chromosome, which is invariably linked to a lack of either physical or mental development or both. This happens during errors in meiosis, the type of cell division that takes place during the development of gametes, which are sex cells that give rise to zygotes during fertilization.

Non-disjunction is a failure of the meiotic process, in which two chromatids or chromosomes pair up and one pole receives nothing. When homologous chromosomes fail to split properly during meiosis I, two defective cells are produced as a result: one has an extra chromosome and the other lacks a chromosome. The chromatids in the chromosomes separate during meiosis II, which may also result in the formation of abnormal cells.

The trisomy on chromosome 21 is more prevalent because the condition is not fatal. Trisomy on a different pair of chromosomes, however, can often be fatal. Having an extra chromosome impacts the way a newborn develops both physically and intellectually. The newborn and future adult may face a variety of mental and physical difficulties as a result of these changes. This is because the DNA in those chromosomes changes how much protein is made and is encoded by them.

The complete question is:

Why are individuals with an extra chromosome 21, which causes Down syndrome, more numerous than individuals with an extra chromosome 3 or chromosome 16?

(A). There are probably more genes on chromosome 21 than on the others.

(B). Chromosome 21 is a sex chromosome, and 3 and 16 are not.

(C). Down syndrome is not more common, just more serious.

(D). Extra copies of the other chromosomes are probably fatal to the developing embryo.

(E). The nondisjunction of chromosomes 3 and 16 probably occurs much less frequently.

To learn more about chromosomal disorders please click on the given link: brainly.com/question/29100880

#SPJ4

5 0
1 year ago
Sickle-cell trait is caused by a single defective allele, but sickle-cell disease only occurs in individuals that are homozygous
Pavel [41]

Answer:

6,25%

Explanation:

Considering that the couple has a trait of sickle cell anemia, we know that both are heterozygous for the disease (Aa) and therefore can have children with the following genotypes:

Parents: Aa X Aa

Children: AA(A x A), Aa(A x a), Aa (a x A) and aa(a x a)

Knowing that sickle cell anemia only occurs in homozygous individuals, the probability for children to have the disease according to each crossing is:

A x A = 1/4 = 25%

A x a = 1/4 = 25%

a x A = 1/4 = 25%

a x a = 1/4 = 25%

The probability of forming each homozygous child (aa) is 1/4 or 25%. Since they are two children, the probability of both having sickle cell anemia is calculated by multiplying the probability of each, so:

1/4 × 1/4 = 1/16 = 0.0625 = 6.25%

It is concluded that the probability of a heterozygous couple for sickle cell anemia to have two children with the disease is 6.25%.

6 0
3 years ago
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