Answer:
yes
Step-by-step explanation:
<h3>1.</h3>
The picture shows 5 groups of 3 bars. Each bar represents 1/10. We take the picture to mean that ...
... (15/10) / 5 = 3/10
In decimal:
... 1.5 / 5 = 0.3
<h3>2.</h3>
The picture shows 3 groups of 2 bars. Each bar represents 1/10. We take the picture to mean that ...
... (6/10) / 3 = 2/10
In decimal:
... 0.6 / 3 = 0.2
<h3>3.</h3>
The picture shows 4 groups, each consisting of 1 large square, 1 bar, and 4 small squares. We take the picture to mean that ...
... (4 + 4/10 + 16/100) / 4 = 1 + 1/10 + 4/100
In decimal:
... 4.56 / 4 = 1.14
Please note that 16/100 is equivalent to 1/10 + 6/100. In order to do the division, one of the 1/10 bars needed to be changed into 10 small squares, 10/100.
<h3>4.</h3>
The picture shows 3 groups, each consisting of 1 large square, 3 bars, and 2 small squares. We take the picture to mean that ...
... (3 + 9/10 +6/100) / 3 = 1 +3/10 + 2/100
In decimal:
... 3.96 / 3 = 1.32
Answer:
No
Step-by-step explanation:
The Side-Angle-Side rule of congruence
two triangles are congruent if two sides and one included angle in a given triangle are equal to the corresponding two sides and one included angle in another triangle.
Answer:
See Explanation
Step-by-step explanation:
Given
Base Dimension
Required
The base area of all containers
First, calculate the base area of 1 container.
This is calculated as:
Express as improper fraction
So, we have:
The number of containers is not given. So, I will use 'n' as the number of containers.
So, we have:
--------------------------------------------------------------------------------------------
Assume n is 3 (i.e. 3 containers)
The total area is:
--------------------------------------------------------------------------------------------
Step-by-step explanation:
It's an irrational number.
![\sqrt[3]{275:7}=\sqrt[3]{\dfrac{275}{7}}=\dfrac{\sqrt[3]{275}}{\sqrt[3]{7}}=\dfrac{\sqrt[3]{275}\cdot\sqrt[3]{7^2}}{\sqrt[3]{7}\cdot\sqrt[3]{7^2}}=\dfrac{\sqrt[3]{275\cdot49}}{\sqrt[3]{7\cdot7^2}}\\\\=\dfrac{\sqrt[3]{13475}}{\sqrt[3]{7^3}}=\dfrac{\sqrt[3]{13475}}{7}=\dfrac{1}{7}\sqrt[3]{13475}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B275%3A7%7D%3D%5Csqrt%5B3%5D%7B%5Cdfrac%7B275%7D%7B7%7D%7D%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7B275%7D%7D%7B%5Csqrt%5B3%5D%7B7%7D%7D%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7B275%7D%5Ccdot%5Csqrt%5B3%5D%7B7%5E2%7D%7D%7B%5Csqrt%5B3%5D%7B7%7D%5Ccdot%5Csqrt%5B3%5D%7B7%5E2%7D%7D%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7B275%5Ccdot49%7D%7D%7B%5Csqrt%5B3%5D%7B7%5Ccdot7%5E2%7D%7D%5C%5C%5C%5C%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7B13475%7D%7D%7B%5Csqrt%5B3%5D%7B7%5E3%7D%7D%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7B13475%7D%7D%7B7%7D%3D%5Cdfrac%7B1%7D%7B7%7D%5Csqrt%5B3%5D%7B13475%7D)
