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Alexxandr [17]
3 years ago
13

Convert 3 √5^2 to fraction

Mathematics
1 answer:
shepuryov [24]3 years ago
4 0

Answer:

15 (simplified)

Step-by-step explanation:

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Three students attempt to define what it means for lines lll and mmm to be perpendicular.
Vanyuwa [196]

Please find diagram attached

Answer and explanation:

Perpendicular lines are lines that meet at 90 degrees/ right angle.

The question seems to be incomplete but I will explain what perpendicular lines are in the context of lines lll and mmm, with some assumptions about the lines.

Assume that line III is 30mm long and line mmm is 25mm long, we say that line III is perpendicular to line mmm if line III meets line mmm at 90 degrees as we see in the diagram attached.

7 0
3 years ago
To create a giant gemstone, sara first made two identical square pyramids that each had a base area of 100 square inches. Then s
inysia [295]

Answer:

8 inches.

Step-by-step explanation:

From the statement we have that they first made two identical square pyramids, each with a base area of 100 square inches.

Ab = s ^ 2 = 100

Therefore each side would be:

s = (100) ^ (1/2)

s = 10

So, side of the square base = 10 inches

Then they tell us that they glued the bases of the pyramids together to form the precious stone. The surface area of the gemstone is 520 square inches, so for a single pyramid it would be:

Ap = 520/2 = 260

For an area of the square pyramid we have the following equation:

Ap = 2 * x * s + s ^ 2

Where x is the height of each triangular surface and s is the side of the square base

Replacing we have:

260 = 2 * x * 10 + 10 ^ 2

20 * x + 100 = 260

20 * x = 160

x = 160/20

x = 8

Therefore, the value of x is 8 inches.

5 0
3 years ago
(a) A natural number that is greater than 25 and less than 40
zloy xaker [14]

<u>Step-by-step explanation:</u>

(a) A natural number that is greater than 25 and less than 40

Natural Number : These are numbers starting from 1 or also sometimes from zero and are all positive !  A natural greater than 25 & less than 40 is 30 .

(b) An integer which is less than -5 and a multiple of 2

Integer : An integer is a whole number not a fraction including 0 . It can be positive or negative ! Integer less than -5 and a multiple of 2 is -6.

(c) A rational number between 1 and 2

Rational Number : A number which can be expressed in form of p/q where q is not equal to 0 . A rational number between 1 & 2 is 3/2 .

(d) An irrational number between 8 and 9.​

Irrational Number: A real number which is not rational or can't be written in form of p/q . An irrational number between 8 & 9 is 6\sqrt{2} .

5 0
2 years ago
What is the largest possible integral value in the domain of the real-valued function
kotegsom [21]

Answer:

Max Value: x = 400

General Formulas and Concepts:

<u>Algebra I</u>

  • Domain is the set of x-values that can be inputted into function f(x)

<u>Calculus</u>

  • Antiderivatives
  • Integral Property: \int {cf(x)} \, dx = c\int {f(x)} \, dx
  • Integration Method: U-Substitution
  • [Integration] Reverse Power Rule: \int {x^n} \, dx = \frac{x^{n+1}}{n+1} + C

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = \frac{1}{\sqrt{800-2x} }

<u>Step 2: Identify Variables</u>

<em>Using U-Substitution, we set variables in order to integrate.</em>

u = 800-2x\\du = -2dx

<u>Step 3: Integrate</u>

  1. Define:                                                                                                            \int {f(x)} \, dx
  2. Substitute:                                                                                         \int {\frac{1}{\sqrt{800-2x} } } \, dx
  3. [Integral] Int Property:                                                                                     -\frac{1}{2} \int {\frac{-2}{\sqrt{800-2x} } } \, dx
  4. [Integral] U-Sub:                                                                                           -\frac{1}{2} \int {\frac{1}{\sqrt{u} } } \, du
  5. [Integral] Rewrite:                                                                                          -\frac{1}{2} \int {u^{-\frac{1}{2} }} \, du
  6. [Integral - Evaluate] Reverse Power Rule:                                                 -\frac{1}{2}(2\sqrt{u}) + C
  7. Simplify:                                                                                                         -\sqrt{u} + C
  8. Back-Substitute:                                                                                            -\sqrt{800-2x} + C
  9. Factor:                                                                                                           -\sqrt{-2(x - 400)} + C

<u>Step 4: Identify Domain</u>

We know from a real number line that we cannot have imaginary numbers. Therefore, we cannot have any negatives under the square root.

Our domain for our integrated function would then have to be (-∞, 400]. Anything past 400 would give us an imaginary number.

7 0
3 years ago
Explain how you got the answer please
kykrilka [37]
-2x + 12 = 2y

Add 2x on both sides,

12 = 2y + 2x

Divide by 2 on both sides,

6 = y + x -> x + y = 6

The answer is D.
4 0
3 years ago
Read 2 more answers
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