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sergij07 [2.7K]
3 years ago
8

Add & subtract comple

Mathematics
1 answer:
Andreyy893 years ago
6 0

Answer:

(-14+3i)-(14i)

14i-3i

= -11i

Answer =(-14+11i)

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8) plsss helpp meeee!!
konstantin123 [22]

Answer:

  \sqrt[n]{x^a}=x^{a/n}

Step-by-step explanation:

While the "law"

  \sqrt[n]{x^n}=x

may seem more applicable, and may seem to be a special case of the law shown in the answer above, it is not true in general. For example, ...

  \sqrt{x^2}=|x|\ne x \quad\text{for x $

6 0
4 years ago
4th grade math patterns 18250, 18500, 19000, 20000 what's the next number?
irinina [24]

22000

The number that's being added in the sequence increases by 2x.

250 * 2 = 500, which is added to 18500 to equal 19000.

500 * 2 = 1000, which is added to 19000 to equal 20000.

1000 * 2 = 2000, which added to 20000 equals 22000.

6 0
4 years ago
Is 26 a perfect square? explain.
Aloiza [94]
No because if you were to square it you would get 5.099 and a perfect square is when it is the same number times each other to get a number for example: the square root of 9 is 3 so 3 times 3 is 9. 
 
Hope that helps!
8 0
3 years ago
Read 2 more answers
Let w(s,t)=f(u(s,t),v(s,t)) where u(1,0)=−6,∂u∂s(1,0)=5,∂u∂1(1,0)=7 v(1,0)=−8,∂v∂s(1,0)=−8,∂v∂t(1,0)=6 ∂f∂u(−6,−8)=−1,∂f∂v(−6,−8
Blababa [14]
w(s,t)=f(u(s,t),v(s,t))

From the given set of conditions, it's likely that you are asked to find the values of \dfrac{\partial w}{\partial s} and \dfrac{\partial w}{\partial t} at the point (s,t)=(1,0).

By the chain rule, the partial derivative with respect to s is

\dfrac{\partial w}{\partial s}=\dfrac{\partial f}{\partial u}\dfrac{\partial u}{\partial s}+\dfrac{\partial f}{\partial v}\dfrac{\partial v}{\partial s}

and so at the point (1,0), we have

\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial s}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial 
v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial s}\bigg|_{(s,t)=(1,0)}
\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=(-1)(5)+(2)(-8)=-21

Similarly, the partial derivative with respect to t would be found via

\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial t}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial 
v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial t}\bigg|_{(s,t)=(1,0)}
\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=(-1)(7)+(2)(6)=5
6 0
4 years ago
12b 40b^2 greatest common factor
SIZIF [17.4K]
12b and 40b^2.

12 and 40 have a greatest common factor of 4.

b^2 and b have a greatest common factor of b.

Therefore, the greatest common factor of the two expressions is 4b.
4 0
3 years ago
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