All categories

3 years ago

The ordered pair (2, 4) is dilated by a scale factor of 1/2, what is the new ordered pair?

Mathematics

1 answer:

rjkz [21]3 years ago

7 0

Answer:

the new pairs are (1, 2)

Step-by-step explanation:

dilation with scale factor 1/2 means the shape will get halved in its image so the ordered pairs will also get halved.

$(2 \times 0.5)(4 \times 0.5) = (1 \: \: \: 2)$

You might be interested in

A prairie dog left its burrow 5 feet underground and started digging deeper into the ground. It digs straight down at a constant

SpyIntel [72]

Building and solving an equation to model the situation, it is found that it takes 4 min for the prairie dog to reach 13 feet underground.

Initially, the dog is 5 feet underground.

Each minute, the dog goes 2 more feet underground.

Hence, the underground height of the dog after t seconds is given by:

$h(t) = 5 + 2t$

The time it takes for the dog to reach 13 feet underground is <u>t for which h(t) = 13</u>, hence:

$h(t) = 5 + 2t$

$13 = 5 + 2t$

$2t = 8$

$t = \frac{8}{2}$

$t = 4$

It takes 4 min for the prairie dog to reach 13 feet underground.

A similar problem is given at brainly.com/question/25290003

7 0

2 years ago

Need help -5(1+2k)-8(-4+5k)

Nataliya [291]

Answer:

27 - 50k

Simplify

1. Distribute

-5 ( 1 + 2k ) - 8 ( -4 + 5k )

-5 - 10k - 8 ( -4 + 5k )

2. Distribute

-5 - 10k - 8 ( -4 + 5k )

-5 - 10k + 32 - 40k

3. Add the numbers

-5 - 10k + 32 - 40k

27 - 10k - 40k

4. Add the same term to both sides of the equation

27 - 10k - 40k

27 - 50k

6 0

3 years ago

What is 12% of 75? =)))

ankoles [38]

Answer:

Hope this helps!

Step-by-step explanation:

12% of 75 would be 9

5 0

2 years ago

Read 2 more answers

Solve please!<br> 2(3√2)2(5+√2)

Dahasolnce [82]

$2\cdot3\sqer2\cdot2(5+\sqrt2)=(2\cdot3\cdot2)\sqrt2(5+\sqrt2)=12\sqrt2(5+\sqrt2)\\\\=60\sqrt2+12\sqrt{2^2}=60\sqrt2+12\cdot2=60\sqrt2+24$

3 0

3 years ago

The differential equation in Example 3 of Section 2.1 is a well-known population model. Suppose the DE is changed to dP dt = P(a

LuckyWell [14K]

Answer:

Decreases

Step-by-step explanation:

We need to determine the integral of the DE;

$dP/dt=P(aP-b)$

$dP=P(aP-b)dt$

$1/(dP^2-bP)dP=dt$

We can solve this by integration by parts on the left side. We expand the fraction 1/P²:

$1/(d-b/P)\cdot{P^2} dP$

let

$u=d-b/P$

$du/dP=b/P^2$

$dP=$ $\int\limits {P^2/b} \, du$

$P=lnu/b$

Substitute u in:

$P=ln(d-b/P)/b$

Therefore the equation is:

$ln(d-b/P)/b=t$

We simplify:

$d-b/P=e^b^t$

$P=b/(d-e^b^t)$

As t increases to infinity P will decrease

6 0

3 years ago