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Nostrana [21]
3 years ago
13

The ordered pair (2, 4) is dilated by a scale factor of 1/2, what is the new ordered pair?

Mathematics
1 answer:
rjkz [21]3 years ago
7 0

Answer:

the new pairs are (1, 2)

Step-by-step explanation:

dilation with scale factor 1/2 means the shape will get halved in its image so the ordered pairs will also get halved.

(2 \times 0.5)(4 \times 0.5) = (1 \:  \:  \: 2)

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Solve the equation.
Musya8 [376]

Answer:

X=11

Step-by-step explanation:

since x=11,11-5=6.

then 6*3=18

5 0
3 years ago
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What are the slope and y-intercept of the graph of the given equation? y = 1.9x + 2.5
trapecia [35]

Answer:

The slope <em>m</em> is 1.9 and the y-intercept <em>b</em> is 2.5.

Step-by-step explanation:

This is in slope-intercept form, y=<em>m</em>x+<em>b</em>, where <em>m</em> is slope and <em>b</em> is the y-intercept.

y = 1.9x + 2.5 means that <em>m </em>is 1.9 and <em>b</em> is 2.5.

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3 years ago
Artemis seeks knowledge of the width of Orion's Belt, which is a pattern of stars in the Orion constellation. She has previously
Verdich [7]

Answer:

Orion's belt width is 184 light years

Step-by-step explanation:

So we want to find the distance between Alnitak and Mintaka, which is the Orions belts

Let the distance between the Alnitak and Mintaka be x,

Then applying cosine

c²=a²+b²—2•a•b•Cosθ

The triangle is formed by the 736 light-years and 915 light years

Artemis from Alnitak is

a = 736lightyear

Artemis from Mintaka is

b = 915 light year

The angle between Alnitak and Mintaka is θ=3°

Then,

Applying the cosine rule

c²=a²+b²—2•a•b•Cosθ

c² =736² + 915² - 2×, 736×915×Cos3

c² = 541,696 + 837,225 - 1,345,034.1477702404

c² = 33,886.85222975954

c = √33,886.85222975954

c = 184.0838184897 light years

c = 184.08 light years

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3 0
3 years ago
What is one of the solutions to the following system of equations? y2 x2 = 53 y − x = 5 (−10, −5) (−7, −2) (7, 2) (5, 10).
Aliun [14]

The solution of the system of equation is (-7, -2).

<h2>Given</h2>

The system of the equations;

\rm y^2 + x^2 = 53 \\\\y -x = 5

From equation 1

\rm  y -x=5\\\\y = 5+x

Substitute the value of y in equation 1

\rm y^2+x^2=53\\\\(5+x)^2+x^2=53\\\\25+x^2+10x+x^2=53\\\\2x^2+10x+25-53=0\\\\2 x^2 + 10x - 28 = 0     \\\\Divide \ by \ 2 \ both \ side \ the \ equation\\\\x^2 + 5x - 14 = 0\\\\x^2-7x+2x-14=0\\\\x(x-7) + 2(x-7) =0\\\\(x-7) \ (x+2)=0\\\\x-7=0 \ \ x = 7\\\\x +2 =0 \ \ x=-2

The value of x= 2 is rejected because x = 2 not satisfy the equation.

Substitute 2 for the value of x in equation II

y − x = 5

y – 2 = 5

y = 5 +2

y = 7 (x =2, y =7) … Not included in the options

If x = -7

Substitute the value of x = -7 in the equation

\rm y -x=5\\\\y - (-7)=5\\\\y +7= 5\\\\y = 5-7\\\\y = -2

Hence, the solution of the system of equation is (-7, -2).

To know more about System of Equation click the link given below.

brainly.com/question/1495351

6 0
2 years ago
HELPPPPP!!!!!!!!
Vlad1618 [11]
The circumcenter of a triangle is the point in the plane equidistant from the three vertices of the triangle. so I believe it is A. True..
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