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Zolol [24]
3 years ago
14

4.Find the length of the diagonal of a rectangle having dimensions 16 cm and 12 cm.

Mathematics
2 answers:
nignag [31]3 years ago
7 0

Answer:

20 cm

Step-by-step explanation:

So from the problem we get that the two sides of the rctangle are 16 cm 12 cm which are base perpendicular of the right angle triangle. H = 20 cm. So the diagonal of the rectangle = 20 cm.

stiks02 [169]3 years ago
7 0

Answer:

20 cm

Step-by-step explanation:

<em>Here's</em><em> your</em><em> solution</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em>> length of rectangle = 16 cm

=> width of rectangle = 12 cm

=> Diagonal of rectangle = √(l^2 + w^2 )

=> Diagonal = √(16^2 + 12^2)

=> Diagonal = √(256 + 144)

=>. Diagonal = √400

=> Diagonal = 20 cm

hope it helps

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2x2 + x - 10

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What does y is two less than x stand for
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Answer:

Y = X - 2 would be the answer.

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A box's volume is equal to 600 cubic
olga2289 [7]

Answer:

Step-by-step explanation:

Length = x

width = x - 7

height = x - 10

volume = 600 in^3

Volume = L * w * h

600 = x * (x - 7)*(x - 10)

600 = x * (x^2 - 17x + 70)

600 = x^3 - 17x^2 + 70x

x^3 - 17x^2 + 70x - 600 = 0

There is a genius somewhere that could solve this using algebra. The rest of us have 2 choices. We can graph it (see below) or we could use a program that solves it for us. I'll do both for you.

a = 1

b  = - 17

c = 70

d = - 600

There is only 1 real solution: x = 15

L = 15

w = 8

h = 5

That has to be one of the ugliest graphs made. It does into the hundreds of thousands and it still looks like a straight line. Trust me. It's not.

3 0
2 years ago
Solve the equation on the interval [0, 2pi): 12cos^2 x-9=0<br><br><br> What to do?
siniylev [52]

Answer:

\large\boxed{x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}\ \vee\ x=\dfrac{7\pi}{6}\ \vee\ x=\dfrac{11\pi}{6}}

Step-by-step explanation:

12\cos^2x-9=0\qquad\text{add 9 to both sides}\\\\12\cos^2x=9\qquad\text{divide both sides by 12}\\\\\cos^2x=\dfrac{9}{12}\\\\\cos^2x=\dfrac{9:3}{12:3}\\\\\cos^2x=\dfrac{3}{4}\to\cos x=\pm\sqrt{\dfrac{3}{4}}\\\\\cos x=\pm\dfrac{\sqrt3}{2}\\\\\text{Look at the picture}\\\\x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}\ \vee\ x=\dfrac{7\pi}{6}\ \vee\ x=\dfrac{11\pi}{6}

6 0
3 years ago
tickets to a play cost 5 dollars for adults and 2 dollars for children. if 1750 tickets were sold for a total of 7100 dollars, h
Sever21 [200]
Let x = number of adults tickets sold
then, 1750 - x = number of children tickets sold

We know that the cost for adult tickets is $5 and and children is above calculated so sum total tickets sold cost is $7100.

($5)(x) + ($2)(1750-x) = $7100
5x - 2x + 3500 = 7100
3x = 3600
x = 1200

8 0
3 years ago
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