We know that
The subtraction property of equality<span> tells us that if we subtract from one side of an equation, we also must subtract from the other side of the equation to keep the equation the same
that means
if a=b and c=d
a-c=b-d
</span>then
<span>−8x+4y=0----------> equation 1
a=(-8x+4y) b=0
−8x+7y=6----------> equation 2
c=(-8x+7y) d=6
therefore
</span>
(-8x+4y)-(-8x+7y)=0-6
-8x+4y+8x-7y=-6
-3y=-6
the answer is the option
Subtraction Property of Equality
if the diameter is 10, its radius is half that, or 5.
![\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=5 \end{cases}\implies V=\cfrac{4\pi (5)^3}{3}\implies V=\cfrac{500\pi }{3} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill V\approx 523.599~\hfill](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20sphere%7D%5C%5C%5C%5C%20V%3D%5Ccfrac%7B4%5Cpi%20r%5E3%7D%7B3%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D5%20%5Cend%7Bcases%7D%5Cimplies%20V%3D%5Ccfrac%7B4%5Cpi%20%285%29%5E3%7D%7B3%7D%5Cimplies%20V%3D%5Ccfrac%7B500%5Cpi%20%7D%7B3%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20V%5Capprox%20523.599~%5Chfill)
Answer:
5 packages . .
Step-by-step explanation:
Range = {-2(-2) - 5, -2(-1) - 5, -2(1) - 5, -2(2) - 5} = {4 - 5, 2 - 5, -2 - 5, -4 - 5} = (-1, -3, -7, -9}
Answer:
1 is the answer
Step-by-step explanation:
-5-(-6) = x
-5 + 6 = x
1 = x
