(x-1)(x-1) + (y+2)(y+2) = 3
x2 -1x -1x + 1 + y2 +2y +2y +4=3
x2 +y2 -2x +4y + 2=0
A is the answer
Answer: a = 18
explanation:
2(a + 10) = 56 -> distribute the 2
2a + 20 = 56 -> subtract 20 from both sides
2a = 56 - 20
2a = 36 -> divide both sides by 2
a = 18
Answer:
x=17, x=-7
Step-by-step explanation:
Step 1 :
Rearrange this Absolute Value Equation
Absolute value equalitiy entered
|x-5|-2 = 10
Another term is moved / added to the right hand side.
|x-5| = 12
Step 2 :
Clear the Absolute Value Bars
Clear the absolute-value bars by splitting the equation into its two cases, one for the Positive case and the other for the Negative case.
The Absolute Value term is |x-5|
For the Negative case we'll use -(x-5)
For the Positive case we'll use (x-5)
Step 3 :
Solve the Negative Case
-(x-5) = 12
Multiply
-x+5 = 12
Rearrange and Add up
-x = 7
Multiply both sides by (-1)
x = -7
Which is the solution for the Negative Case
Step 4 :
Solve the Positive Case
(x-5) = 12
Rearrange and Add up
x = 17
Which is the solution for the Positive Case
Step 5 :
Wrap up the solution
x=-7
x=17
Answer:
o
Step-by-step explanation:
-4h=32
h=32/-4
h=-8
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