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Ivahew [28]
3 years ago
13

1) El ritmo cardíaco de un gato ( en latidos por minuto) es función lineal de su temperatura corporal (en grados Celsius). En co

ndiciones normales un gato con 37°C tiene un ritmo cardíaco de 200 pulsaciones por minuto y de 150 si su temperatura es de 32°C.
Mathematics
1 answer:
olga55 [171]3 years ago
6 0

Answer:

y=10x-170

Step-by-step explanation:

This problem can be modeled by a linear function, where we have two points (37°C, 200) and (32°C, 150).

Notice that the temperature is the independent variable, because the heartbeat of the cat won't change the temperature, it works in the opposite way.

First, let's find the constant ratio of change.

m=\frac{150-200}{32-37}=\frac{-50}{-5}=10

This means the hearbeat of the car changes 10 pulses per minute each 1 celsius degree.

Now, we use the point slope formula to find the equation

y-y_{1} =m(x-x_{1} )\\y-150=10(x-32)\\y=10x-320+150\\y=10x-170

Theerefore, the function that represents this situation is

y=10x-170

Where x represents temperature and y represents hearbeats.

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3 years ago
.A bag contains 3 red checkers and 5 black checkers. A checker is selected, kept out of the bag, and then another checker is sel
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Answer: 15 / 56

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Number of red checkers = 3

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Total number of checkers = 8

P(black, then red) = 5/8 × 3/7 = 15/56

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2 years ago
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A will get (7000×1) = #7000

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Answer:2

Step-by-step explanation:

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