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2 years ago

How do i do this? i’m having trouble

Mathematics

1 answer:

Fantom [35]2 years ago

6 0

Answer:

121

Step-by-step explanation:

5x-54=3x+16

5x-3x=16+54

2x=70

x=35

-------

mAB= 5x-54= 5*35-54= 175-54= 121

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SERIOULSLY WOULD SOMEONE JUST HELP ME WITH THESE QUESTIONS FOR ONCE? BY THAT I MEAN NOT ONLY ANSWER 23 AND 22 ALSO 24, 25, 26,27

Fantom [35]

Answer:

Step-by-step explanation:

22. √125 is closer to √121 or 11

23. √23.5 is closer to √25 or 5

24. ∛59 is closer to ∛64 or 4 (cubed)

(4 cubed = 64, 3 cubed = 27)

25. ∛430 is closer to ∛512 or 8

(512 - 430 = 82

430- 343= 87)

26. y² = 55 is equal to y = √55, Closer to √49 or 7

27. d² = 95 is equal to d = √95, Closer to √100 or 10

28. p² = 6.8 is equal to p = √6.8, Closer to √9 or 3

29. ∛210 is closer to ∛216 or 6 (cubed)

30. ∛520 is closer to ∛512 or 8 (cubed)

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3 years ago

A new hybrid car has a 18-gallon gas tank. On one tank of gas, the owner can drive 540 miles. The number of miles traveled varie

tensa zangetsu [6.8K]

To find the amount of miles/gallon, we have 540 miles/18 gallons=30 miles/gallon. As we add 30 miles for every gallon, the amount of miles traveled is 30*x (e.g. if x is 1 then 0+30=30 and if x is 2 then 30+30 (2 times)=60) with x being the amount of gallons. For b, we just plug 12 in for x to get 20*12=360

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2 years ago

A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he

UkoKoshka [18]

Answer:

a) The minimum sample size is 601.

b) The minimum sample size is 2401.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

For this problem, we have that:

We dont know the true proportion, so we use $\pi = 0.5$ , which is when we are are going to need the largest sample size.

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

a. If a 95% confidence interval with a margin of error of no more than 0.04 is desired, give a close estimate of the minimum sample size that will guarantee that the desired margin of error is achieved. (Remember to round up any result, if necessary.)

This is n for which M = 0.04. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.04\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.04}$

$(\sqrt{n})^2 = (\frac{1.96*0.5}{0.04})^2$

$n = 600.25$

Rounding up

The minimum sample size is 601.

b. If a 95% confidence interval with a margin of error of no more than 0.02 is desired, give a close estimate of the minimum sample size necessary to achieve the desired margin of error.

Now we want n for which M = 0.02. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.02 = 1.96\sqrt{\frac{0.5*0.5}{n}}$