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lisov135 [29]
3 years ago
5

In The cafeteria, 100 milk cartons were put out for breakfast. At the end of breakfast, 27 remained. What is the ratio

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
7 0
Number of milk cartons put out for breakfast = 100

Number of cartons remaining at the end = 27

Number of cartons consumed = 100 - 27 = 73

Ratio of cartons remaining / cartons consumed = 27/73
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sergiy2304 [10]
4.2× 3600 = 15120 seconds
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15<br> G<br> F<br> H<br> 4) What is the value of x?<br> A) 10<br> B) 12<br> C) 15<br> D) 17
coldgirl [10]

Answer:

C) 15

Step-by-step explanation:

This is an isosceles triangle (two of the three angles are equal) so two of the sides are also equal. x is the same length as 15.

5 0
2 years ago
Which pair of lines is parallel? A. y=4x+1 and y+4=5 B. y=-2+x and 2y-2x=-2 C. y=1/4x + 2 and y-2=1/2x D. y=1/5x+1 and 5y+x= 10
sdas [7]

Answer:

B. y=-2+x and 2y-2x=-2

Step-by-step explanation:

Two lines are parallel if they have the same slope.

The equation 0of a line is tipically written as y=mx + b, where 'm' represents the slope and 'b' the y-intercept.

Let's evaluate each of the options:

A. y=4x+1 and y+4x=5

Writing the equations in the slope-intercept form, we get:

y=4x+1 → m=4

y=5-4x → m=-4

Given that they have different slopes, they are not parallel.

B. y=-2+x and 2y-2x=-2

Writing the equations in the slope-intercept form, we get:

y=-2+x → m=1

y=-1 + x → m=1

Given that the equations have the same slope, they are parallel.

C. y=1/4x + 2 and y-2=1/2x

Writing the equations in the slope-intercept form, we get:

y=1/4x + 2  → m=1/4

y=1/2x+2 → m=1/2

Given that they have different slopes, they are not parallel.

D. y=1/5x+1 and 5y+x= 10

Writing the equations in the slope-intercept form, we get:

y=1/5x+1 → m=1/5

5y+x= 10 → y=2 - 1/5x → m=-1/5

Given that they have different slopes, they are not parallel.

4 0
3 years ago
Which polynomial represents the sum below?<br> (3x2 + 3) + (3x2 + x + 4)
DIA [1.3K]
Add like terms just like you would anywhere else...6 x^{2} +x+7
6 0
3 years ago
Verify the identity 6cos^2(x) -3 = 3 - 6sin^2(x)
Lorico [155]

Answer:

It is proved that  6\cos ^{2}x -3 = 3 - 6\sin ^{2} x .

Step-by-step explanation:

We already have the identity of x as \sin ^{2}x + \cos ^{2}x = 1 .......... (1)  .

So, from equation (1) we can write that

\cos ^{2} x = 1 - \sin ^{2} x

⇒ 6\cos ^{2} x = 6 - 6 \sin ^{2} x

⇒ 6\cos ^{2} x -3 = 6 - 6 \sin ^{2}x -3

⇒ 6\cos ^{2}x -3 = 3 - 6\sin ^{2} x

Hence, it is proved that  6\cos ^{2}x -3 = 3 - 6\sin ^{2} x . (Answer)

5 0
3 years ago
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