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MariettaO [177]
3 years ago
10

Write these numbers as fractions. Simplify the answers. 0.5, 12.3, 0.07, 0.625

Mathematics
2 answers:
kotykmax [81]3 years ago
5 0

Answer:

see below

Step-by-step explanation:

0.5, 5/10 = 1/2

12.3 = 12 3/10

0.07 = 07/100

0.625=625/1000 =5/8

motikmotik3 years ago
4 0

0.5 => 5/10 => 1/2

12.3 => 123/10

0.07 => 7/100

0.625 => 625/1000 => 25/40 => 5/8

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Michael
KengaRu [80]

Answer:

I believe the answer should be 90%

4 0
3 years ago
X-4=-11 please work problem out it’s homework need help
alisha [4.7K]

X-4=-11

move -4 to the other side

to get X by itself

sign changes from -4 to +4

X-4+4= -11+4

X= -11+4

Answer:

X= -7

5 0
3 years ago
The revenue from selling x shirts is r(x) = 11x. The cost of buying x shirts is c(x) = 6x + 20. The profit from selling x shirts
oee [108]

Answer: option A is the correct answer.

Step-by-step explanation:

The expression that relates revenue, profit and cost is

Profit = Revenue - Cost

The revenue from selling x shirts is r(x) = 11x. The cost of buying x shirts is c(x) = 6x + 20. Therefore,

p(x) = r(x) - c(x)

p(x) = 11x - (6x + 20)

By expanding the bracket, the minus sign will alter each term in the bracket. Therefore,

p(x) = 11x - 6x - 20

p(x) = 5x - 20

8 0
3 years ago
What is 4/5 x for x =5/8? HALP pls
lana [24]
1/2.That's the answer.
7 0
4 years ago
in a certain chemical, the ratio if zinc to copper is 3 to 16. a jar of the chemical contains 320 grams of copper. how many gram
Dennis_Churaev [7]

Answer:

60 grams

Step-by-step explanation:

For these type of questions, we can equate the ratio with the actual amounts. We will let the quantity to find be an unknown variable, such as x. Then we equate the ratios, cross multiply, and use algebra to solve.

Let grams of zinc be "x", so we can write the ratios and actual amounts as:

\frac{3}{16}=\frac{x}{320}

Then we cross multiply and solve for x, what we want to find out. Shown below:

\frac{3}{16}=\frac{x}{320}\\16x =3 * 320\\16x = 960\\x = \frac{960}{16}\\x=60

There are 60 grams of zinc.

5 0
4 years ago
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