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Ivan
3 years ago
10

On Monday, the coldest temperature outside was 2 degrees Fahrenheit. On Tuesday, Ms. Perkins tells her students that the coldest

temperature outside has an absolute value of 4 degrees.
Rachel says that Tuesday’s coldest temperature could be greater than Monday’s coldest temperature.

Tom says that Tuesday’s coldest temperature could be less than Monday’s coldest temperature.

State whether each student’s statement is true or false, and justify your answers.


PLS I NEED THIS ITS ALL MY POINTS DONT TROLL

ALSO EXPLAIN IT
Mathematics
2 answers:
Lerok [7]3 years ago
7 0

Answer:

Temperature on Monday was 2 degrees Fahrenheit.

Temperature on Tuesday was absolute value of 4 degrees Fahrenheit.

Absolute value is always a positive number but the actual temperature could have been positive or negative 4 degrees.

  • | ± 4 | = 4

If it was positive, then Rachel is correct, but if negative, then Tom is correct.

vfiekz [6]3 years ago
7 0

ANSWER:

Both of the students answer may be correct because it is not clear either it is + 4°F or - 4°F.

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3. A team of eye surgeons has developed a new technique for a risky eye operation to restore the
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Yes the new method if sample size was less than 20 than that of old method or identical sample numbers of old and new the differences still prove the new operation is better. As 88 patients minus 1% still shows us 76.7475 significance of  old method being low point 67.5 = 30% of 225 and proved a 65.25 low point and 69.75 high point which is also a 20% jump to new methods low point significance.

You cna show this as workings to prove or follow any of the below statements.

Where new method of 88 patients -0.01 significance rate stands at 76.7475. This figure has reduced by 11.2525 from 88 patients to 76.7 we compare this to the old method if reversing significance we find  = 62.5 and it's 30% standing value of 67.5  as +1% increase shows us 31% = 69.7  ( 0.31 x 225 = 69.74)

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88/225  = 0.39111111111 = 39.11%%

P value 01 = 1%  =  225.225 or 5% range of alternative hypotheses.

To graph the P value we take the distance between the sample mean and the null hypothesis value (225 + 1% of sample - x nhv) = y ). We can graph the probability of obtaining a sample mean  (225 +/- ( x +1% of sample) where nhv has a decimal if needed to utilize the 1% added). we would replace nvp in this example with  Ha or H1 which means the alternative hypotheses as the data shows less than or equal to.

We can then show 225.225 -  Ha or H1  then graph the probability of obtaining a sample mean that is at least extreme in both tails  Ha or H1

However it would be the other way round where you take the first set of data and use the sample as the 30% significance of that sample indicates it may be a larger sample or a higher significance. Therefore this would be used in the graphing - 1%

We prove that 30-1 =29  where 29% of 225 = 225 x 0.29 = 65.25

this way we have proved that the new set of data being equal to 88 patients regaining their eyesight is <23 and can be written like this 65.25< x <88

This means that sample mean has taken the 1% to show on the graph we can show 225> 33.11 +1 .

We can prove that both indifference of significance would reduce when 1% is added and close based on being a higher percentage to begin with.

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76.5475 - 67.5 = 9.04 difference when comparing old method = +1%

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