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2 years ago

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On Monday, the coldest temperature outside was 2 degrees Fahrenheit. On Tuesday, Ms. Perkins tells her students that the coldest

temperature outside has an absolute value of 4 degrees.
Rachel says that Tuesday’s coldest temperature could be greater than Monday’s coldest temperature.

Tom says that Tuesday’s coldest temperature could be less than Monday’s coldest temperature.

State whether each student’s statement is true or false, and justify your answers.

PLS I NEED THIS ITS ALL MY POINTS DONT TROLL

ALSO EXPLAIN IT

2 answers:

Lerok [7]2 years ago

7 0

Answer:

Temperature on Monday was 2 degrees Fahrenheit.

Temperature on Tuesday was absolute value of 4 degrees Fahrenheit.

Absolute value is always a positive number but the actual temperature could have been positive or negative 4 degrees.

| ± 4 | = 4

If it was positive, then Rachel is correct, but if negative, then Tom is correct.

vfiekz [6]2 years ago

7 0

ANSWER:

Both of the students answer may be correct because it is not clear either it is + 4°F or - 4°F.

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The second sample mean is $\= x _2 = 10$

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$SE_1 = \frac{\sigma_1}{\sqrt{n} }$

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Generally the second standard error is

$SE_2 = \frac{\sigma_2}{\sqrt{n} }$

$SE_2 = \frac{0.742}{\sqrt{60} }$

$SE_2 = 0.09$

Generally the standard error of the difference between their mean scores is mathematically represented as

$SE = \sqrt{SE_1^2 + SE_2^2 }$

=> $SE = \sqrt{0.06^2 +0.09^2 }$

=> $SE = 0.66}$

Generally 95% confidence interval is mathematically represented as

$(\= x_1 -\= x_2) -(Z_{\frac{\alpha }{2} } * SE) < \mu_1 - \mu_2 < (\= x_1 -\= x_2) +(Z_{\frac{\alpha }{2} } * SE)$

=> $(8 -10) -(1.96 * 0.66) < \mu_1 - \mu_2 < (8-10) +(Z_{\frac{\alpha }{2} } * 0.66)$

=> $-3.29 < \mu_1 - \mu_2 < -0.70$

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